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A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.
- a)0.0382
- b)0.0386
Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer?
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Verified Answer
A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lub...
d = diameter, C = diametral clearance
Z2 = 0.0384 kg/m.s
Most Upvoted Answer
A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lub...
Calculation of Lubricant Flow Rate:
• The bearing diameter is 50 mm, and the shaft speed is 320 rpm.
• The circumferential velocity of the bearing is (π x D x N) / 60 = (3.14 x 50 x 320) / 60 = 267 m/min.
• The lubricant flow rate (Q) is given by Q = (π x D x L x p) / (4 x μ x C), where L is the length of the bearing, p is the bearing pressure, μ is the viscosity of the lubricant, and C is the diametral clearance.
• Substituting the given values, we get Q = (3.14 x 50 x L x 1.5) / (4 x 0.06 x 0.15) = 294.44 L/min.
Calculation of Required Viscosity:
• The bearing pressure is 1.5 N/mm2, and the diametral clearance is 0.12 mm.
• The lubricant flow rate (Q) is the same as before, i.e., 294.44 L/min.
• The required viscosity (μ') can be calculated by rearranging the equation for Q as μ' = (π x D x L x p) / (4 x Q x C).
• Substituting the given values, we get μ' = (3.14 x 50 x L x 1.5) / (4 x 294.44 x 0.12) = 0.0384 kg/m.s (approx).
• Therefore, the change made for the viscosity is (μ' - μ) = 0.0384 - 0.06 = 0.0216 kg/m.s (approx).
Final Answer:
The change made for the viscosity is 0.0384 - 0.06 = 0.0216 kg/m.s (approx). The correct answer is between 0.0382 and 0.0386.
• The bearing diameter is 50 mm, and the shaft speed is 320 rpm.
• The circumferential velocity of the bearing is (π x D x N) / 60 = (3.14 x 50 x 320) / 60 = 267 m/min.
• The lubricant flow rate (Q) is given by Q = (π x D x L x p) / (4 x μ x C), where L is the length of the bearing, p is the bearing pressure, μ is the viscosity of the lubricant, and C is the diametral clearance.
• Substituting the given values, we get Q = (3.14 x 50 x L x 1.5) / (4 x 0.06 x 0.15) = 294.44 L/min.
Calculation of Required Viscosity:
• The bearing pressure is 1.5 N/mm2, and the diametral clearance is 0.12 mm.
• The lubricant flow rate (Q) is the same as before, i.e., 294.44 L/min.
• The required viscosity (μ') can be calculated by rearranging the equation for Q as μ' = (π x D x L x p) / (4 x Q x C).
• Substituting the given values, we get μ' = (3.14 x 50 x L x 1.5) / (4 x 294.44 x 0.12) = 0.0384 kg/m.s (approx).
• Therefore, the change made for the viscosity is (μ' - μ) = 0.0384 - 0.06 = 0.0216 kg/m.s (approx).
Final Answer:
The change made for the viscosity is 0.0384 - 0.06 = 0.0216 kg/m.s (approx). The correct answer is between 0.0382 and 0.0386.
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A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer?
Question Description
A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer?.
A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer?.
Solutions for A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer?, a detailed solution for A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? has been provided alongside types of A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A bearing of 50 mm in diameter has a shaft speed of 320 rpm and a lubricating oil of viscosity 0.06 kg/m.s. The diametral clearance is 0.15 mm and the bearing pressure is 1.5 N/mm2 . If it is designed for a speed of 320 rpm and pressure of 1.5 N/2mm . Clearance of 0.12 mm, the change made for the viscosity is (in kg/m.s) is __________.a) 0.0382b) 0.0386Correct answer is between ' 0.0382, 0.0386'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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