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Consider an infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm. The view factor from 2 cm side to 4 cm side is __________.
- a)0.58
- b)0.59
Correct answer is option ''. Can you explain this answer?
Most Upvoted Answer
Consider an infinitely long three sided triangular enclosure with sid...
Given la = 2 cm
Lb = 3 cm
Lc = 4 cm
By energyF conservation principle
Faa + Fab + Fac = 1
Fba + Fbb + Fbc = 1
Fca + Fcb + Fcc = 1
As a,b,c are planar surfaces
Faa, Fbb, Fcc, = 0
Therefore the equations are reduced to
Fab + Fac = 1 ….①
Fba + Fbc + = 1 ...②
Fca + Fcb = 1 ….③
By Reciprocity theorem
Substituting Fba & Fbc in equation ②
Substituting Fcb & Fca in equation ③
∴ 2Fac - 6Fab = 1
Fac - 3Fab = 1/2 ….Ⓢ
Solving equation ① & Ⓢ together
Fab + Fac =1
Fac - 3Fab = 1/2
____________
3Fab + 3ac = 3
3Fac - 3Fab = 1/2
+ + +
______________
6Fac = 7/2
Fac = 7/12
Fac 0.5833
Question_type 5
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Consider an infinitely long three sided triangular enclosure with sid...
Solution:
Given: An infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm.
To find: The view factor from 2 cm side to 4 cm side.
View Factor:
The view factor is the proportion of the radiation leaving the surface that is intercepted by another surface. It is represented by Fij, where i and j are the two surfaces considered.
View factor from 2 cm side to 4 cm side:
To calculate the view factor, we can use the formula:
F12 = (A1/A2) × (cosθ1/cosθ2)
Where,
F12 = view factor from surface 1 to surface 2
A1 and A2 = surface areas of surface 1 and surface 2, respectively
θ1 and θ2 = angles between the two surfaces and the line normal to the surface
Here, the view factor from 2 cm side to 4 cm side can be calculated as follows:
Consider surfaces 1 and 2 as shown below:
From the above figure, we can see that:
A1 = 2 × √5/2 = √20 cm^2
A2 = 4 × √7/2 = √56 cm^2
θ1 = 90°
θ2 = tan^-1(3/4) = 36.87°
Substituting these values in the formula, we get:
F12 = (√20/√56) × (1/0.766) = 0.59
Therefore, the view factor from 2 cm side to 4 cm side is 0.59 (approximately). Hence, option (b) is the correct answer.
Given: An infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm.
To find: The view factor from 2 cm side to 4 cm side.
View Factor:
The view factor is the proportion of the radiation leaving the surface that is intercepted by another surface. It is represented by Fij, where i and j are the two surfaces considered.
View factor from 2 cm side to 4 cm side:
To calculate the view factor, we can use the formula:
F12 = (A1/A2) × (cosθ1/cosθ2)
Where,
F12 = view factor from surface 1 to surface 2
A1 and A2 = surface areas of surface 1 and surface 2, respectively
θ1 and θ2 = angles between the two surfaces and the line normal to the surface
Here, the view factor from 2 cm side to 4 cm side can be calculated as follows:
Consider surfaces 1 and 2 as shown below:
From the above figure, we can see that:
A1 = 2 × √5/2 = √20 cm^2
A2 = 4 × √7/2 = √56 cm^2
θ1 = 90°
θ2 = tan^-1(3/4) = 36.87°
Substituting these values in the formula, we get:
F12 = (√20/√56) × (1/0.766) = 0.59
Therefore, the view factor from 2 cm side to 4 cm side is 0.59 (approximately). Hence, option (b) is the correct answer.
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Consider an infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm. The view factor from 2 cm side to 4 cm side is __________.a) 0.58b) 0.59Correct answer is option ''. Can you explain this answer? for Chemical Engineering 2025 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Consider an infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm. The view factor from 2 cm side to 4 cm side is __________.a) 0.58b) 0.59Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm. The view factor from 2 cm side to 4 cm side is __________.a) 0.58b) 0.59Correct answer is option ''. Can you explain this answer?.
Consider an infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm. The view factor from 2 cm side to 4 cm side is __________.a) 0.58b) 0.59Correct answer is option ''. Can you explain this answer? for Chemical Engineering 2025 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Consider an infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm. The view factor from 2 cm side to 4 cm side is __________.a) 0.58b) 0.59Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an infinitely long three sided triangular enclosure with sides 2 cm, 3 cm and 4 cm. The view factor from 2 cm side to 4 cm side is __________.a) 0.58b) 0.59Correct answer is option ''. Can you explain this answer?.
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