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On an overcast day the directional distribution of the solar radiation incident on the earth’s surface may be approximated by an expression of the form where In = 80 W/m2is the total intensity of radiation directed normal to the surface and is the zenith angle. What is the solar irradiation at the earth’s surface?
- a)250
- b)252
Correct answer is between ' 250, 252'. Can you explain this answer?
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On an overcast day the directional distribution of the solar radiatio...
Consider a point on the earth’s surface receiving solar radiation from all hemispherical directions above the point.
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By definition of intensity of radiation
dQ1 = I(dA1 cos ፀ)ωdA2➝dA1 where dA2 is a small area on hemispherical surface.
∴ ωdA2➝dA1 = (rsin ፀ dф)(rdፀ)/r2
= sin ፀ dፀ dф
∴ dQ1 - IdA1 sin θ dθ dф
dQ1 - Incos ө dA1 sin θ dθ dф
dQ1 - IndA1 sin 2θ/2 x dθ dф
G = Qi/dA1 =In x π
∴ G = 80 x π
G = 251.32 W/m2
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On an overcast day the directional distribution of the solar radiatio...
Calculation of Solar Irradiation at Earth's Surface:
Given:
- Total intensity of radiation directed normal to the surface (In) = 80 W/m2
- Zenith angle () is the angle between the sun and the vertical line drawn at a specific location on the earth's surface
Expression for Solar Radiation Distribution:
- The directional distribution of solar radiation incident on the earth's surface can be approximated by the expression:
= In * cos()
Calculation:
- Substituting the given value of In = 80 W/m2 into the expression, we get:
= 80 * cos()
- Since the zenith angle varies throughout the day, we need to consider the average value of cos() over the entire day.
- The average value of cos() over a full day is 0.5.
Therefore, the Solar Irradiation at Earth's Surface:
= 80 * 0.5
= 40 W/m2
Therefore, the solar irradiation at the earth's surface is 40 W/m2. This represents the average solar radiation received on an overcast day considering the directional distribution of sunlight.
Given:
- Total intensity of radiation directed normal to the surface (In) = 80 W/m2
- Zenith angle () is the angle between the sun and the vertical line drawn at a specific location on the earth's surface
Expression for Solar Radiation Distribution:
- The directional distribution of solar radiation incident on the earth's surface can be approximated by the expression:
= In * cos()
Calculation:
- Substituting the given value of In = 80 W/m2 into the expression, we get:
= 80 * cos()
- Since the zenith angle varies throughout the day, we need to consider the average value of cos() over the entire day.
- The average value of cos() over a full day is 0.5.
Therefore, the Solar Irradiation at Earth's Surface:
= 80 * 0.5
= 40 W/m2
Therefore, the solar irradiation at the earth's surface is 40 W/m2. This represents the average solar radiation received on an overcast day considering the directional distribution of sunlight.
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On an overcast day the directional distribution of the solar radiatio...
Consider a point on the earth’s surface receiving solar radiation from all hemispherical directions above the point.
By definition of intensity of radiation
dQ1 = I(dA1 cos ፀ)ωdA2➝dA1 where dA2 is a small area on hemispherical surface.
∴ ωdA2➝dA1 = (rsin ፀ dф)(rdፀ)/r2
= sin ፀ dፀ dф
∴ dQ1 - IdA1 sin θ dθ dф
dQ1 - Incos ө dA1 sin θ dθ dф
dQ1 - IndA1 sin 2θ/2 x dθ dф
G = Qi/dA1 =In x π
∴ G = 80 x π
G = 251.32 W/m2
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On an overcast day the directional distribution of the solar radiation incident on the earth’s surface may be approximated by an expression of the form where In = 80 W/m2is the total intensity of radiation directed normal to the surface and is the zenith angle. What is the solar irradiation at the earth’s surface?a) 250b) 252Correct answer is between ' 250, 252'. Can you explain this answer?
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On an overcast day the directional distribution of the solar radiation incident on the earth’s surface may be approximated by an expression of the form where In = 80 W/m2is the total intensity of radiation directed normal to the surface and is the zenith angle. What is the solar irradiation at the earth’s surface?a) 250b) 252Correct answer is between ' 250, 252'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about On an overcast day the directional distribution of the solar radiation incident on the earth’s surface may be approximated by an expression of the form where In = 80 W/m2is the total intensity of radiation directed normal to the surface and is the zenith angle. What is the solar irradiation at the earth’s surface?a) 250b) 252Correct answer is between ' 250, 252'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On an overcast day the directional distribution of the solar radiation incident on the earth’s surface may be approximated by an expression of the form where In = 80 W/m2is the total intensity of radiation directed normal to the surface and is the zenith angle. What is the solar irradiation at the earth’s surface?a) 250b) 252Correct answer is between ' 250, 252'. Can you explain this answer?.
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