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In the previous question if εshield = εsurface, then what will be the number of shields?
Option~
(A) 100
(B) 3
(C) 99
(D) 4
Correct answer is 'C'. Can you explain this answer?
Verified Answer
In the previous question if εshield = εsurface, then what will be the...
With introduction of n shields the rate of heat transfer reduces by 99%, therefore,
1.5/1.5+1.5n = 0.01
n = 1.5(1-0.01)/1.5 x 0.01
n = 99
This shows that if the emissivity of the surface is large then number of shields should be large as shield shall offer less resistance. Hence for shields to be effective their surface emissivity should be as low as possible.
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Most Upvoted Answer
In the previous question if εshield = εsurface, then what will be the...
With introduction of n shields the rate of heat transfer reduces by 99%, therefore,
1.5/1.5+1.5n = 0.01
n = 1.5(1-0.01)/1.5 x 0.01
n = 99
This shows that if the emissivity of the surface is large then number of shields should be large as shield shall offer less resistance. Hence for shields to be effective their surface emissivity should be as low as possible.
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Community Answer
In the previous question if εshield = εsurface, then what will be the...
With introduction of n shields the rate of heat transfer reduces by 99%, therefore,
1.5/1.5+1.5n = 0.01
n = 1.5(1-0.01)/1.5 x 0.01
n = 99
This shows that if the emissivity of the surface is large then number of shields should be large as shield shall offer less resistance. Hence for shields to be effective their surface emissivity should be as low as possible.
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