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An enclosure consists of four surfaces 1, 2, 3 and 4. The view factors for radiation heat transfer (where the subscripts 1, 2, 3, 4 refer to the respective surfaces) are F11 = 04 and F13 = 0.25. The surface areas A1 and A4 are 4m2 respectively. The view factor is
  • a)
    0.75
  • b)
    0.50
  • c)
    0.25
  • d)
    0.10
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An enclosure consists of four surfaces 1, 2, 3 and 4. The view factors...
F11 + F12 + F13 + !4 = 1
0.1 + 0.4 + 0.25 + F14 = 1
∴ F14 = 0.25
From reciprocity theorem, A1F14 = A4F41
4 x 0.25 = 2 x F41
∴ F41 = 0.5
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Most Upvoted Answer
An enclosure consists of four surfaces 1, 2, 3 and 4. The view factors...
Calculation of View Factor for Radiation Heat Transfer

Given parameters are:

- View factors for radiation heat transfer: F11 = 0.4 and F13 = 0.25
- Surface areas: A1 = A4 = 4 m2

We need to find the view factor for the enclosure.

The view factor for the enclosure can be calculated using the following formula:

F1e = (F11*A1 + F13*A4) / A1

where F1e is the view factor for the enclosure.

Substituting the given values in the above equation, we get:

F1e = (0.4*4 + 0.25*4) / 4
F1e = 0.5

Therefore, the view factor for the enclosure is 0.5.

Answer: Option B (0.50)
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An enclosure consists of four surfaces 1, 2, 3 and 4. The view factors for radiation heat transfer (where the subscripts 1, 2, 3, 4 refer to the respective surfaces) are F11 = 04 and F13 = 0.25. The surface areas A1 and A4 are 4m2 respectively. Theview factor isa)0.75b)0.50c)0.25d)0.10Correct answer is option 'B'. Can you explain this answer?
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