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The spectral hemispherical absorptivity of an opaque surface is as shown.
The surface is exposed to ir-radiation for which the spectral distribution is as shown.
What is the total hemispherical absorptivity of surface?
- a)0.6
- b)0.8
- c)0.7
- d)Data insufficient
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The spectral hemispherical absorptivity of an opaque surface is as sho...
Total absorptivity is defined as
α = Ga/G
Where Ga = ∫oooαλGλdλ
Ga = ∫06 0.6 x 0 dλ + ∫610 0.8 x 500 dλ + ∫1014 0.8 x 250 dλ + ∫1400 0.8 x 0 dλ
∴ Ga = 0 + 0.8 x 500 x (10-6) + 0.8 x 250 x (14-10) + 0
Ga = 2400 W/m2 ...①
and
G = ∫000 Gλdλ
I.e. G = Area under graph Gλ Vs λ
G = 500 x (10-6) + 250 x (14-10)
G = 2000 + 1000
G = 3000 W/m2 ...②
Therefore, from ① & ②
α = Ga/G = 2400/3000
α = 0.8
Most Upvoted Answer
The spectral hemispherical absorptivity of an opaque surface is as sho...
Total absorptivity is defined as
α = Ga/G
Where Ga = ∫oooαλGλdλ
Ga = ∫06 0.6 x 0 dλ + ∫610 0.8 x 500 dλ + ∫1014 0.8 x 250 dλ + ∫1400 0.8 x 0 dλ
∴ Ga = 0 + 0.8 x 500 x (10-6) + 0.8 x 250 x (14-10) + 0
Ga = 2400 W/m2 ...①
and
G = ∫000 Gλdλ
I.e. G = Area under graph Gλ Vs λ
G = 500 x (10-6) + 250 x (14-10)
G = 2000 + 1000
G = 3000 W/m2 ...②
Therefore, from ① & ②
α = Ga/G = 2400/3000
α = 0.8
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Community Answer
The spectral hemispherical absorptivity of an opaque surface is as sho...
Total absorptivity is defined as
α = Ga/G
Where Ga = ∫oooαλGλdλ
Ga = ∫06 0.6 x 0 dλ + ∫610 0.8 x 500 dλ + ∫1014 0.8 x 250 dλ + ∫1400 0.8 x 0 dλ
∴ Ga = 0 + 0.8 x 500 x (10-6) + 0.8 x 250 x (14-10) + 0
Ga = 2400 W/m2 ...①
and
G = ∫000 Gλdλ
I.e. G = Area under graph Gλ Vs λ
G = 500 x (10-6) + 250 x (14-10)
G = 2000 + 1000
G = 3000 W/m2 ...②
Therefore, from ① & ②
α = Ga/G = 2400/3000
α = 0.8
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The spectral hemispherical absorptivity of an opaque surface is as shown.The surface is exposed to ir-radiation for which the spectral distribution is as shown.What is the total hemispherical absorptivity of surface?a)0.6b)0.8c)0.7d)Data insufficientCorrect answer is option 'B'. Can you explain this answer?
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