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A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.
- a)23800
- b)23950
Correct answer is between ' 23800, 23950'. Can you explain this answer?
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Verified Answer
A forged steel bar of 50 mm diameter, is subjected to a reversed bend...
Sf = 250 N/mm2
Sut = 600 N/mm2
Se = 101N/mm2
The S-N curve consists of a straight line (AB) drawn from 0.9 Sut at 103 cycles to at cycles at Se = 106 on log graph
0.9 sut = 0.9 x 600 = 540 N/mm2
log10 (0.9 sut) = log10(540) = 2.7323
log10(Se) = log10(101) = 20043
log10(sf) = log10(250) = 2.3979
log10(103) = 3
log10 (106) = 6
Fatigue life of bar, from figure
= 4.3782
log10 N = 4.3782
N = 23889.1 cycle
Therefore,log10 N = 3 + EF = 3 + 1.3782
Most Upvoted Answer
A forged steel bar of 50 mm diameter, is subjected to a reversed bend...
Given data:
Diameter of forged steel bar (d) = 50 mm
Reversed bending stress (σ) = 250 N/mm²
Steel material = 40 C8 mm (Sut = 600 N/mm²)
Corrected endurance limit (Se) = 101 N/mm²
To find: Life of the steel bar in cycles
Solution:
Step 1: Calculation of mean stress (σm)
As the stress is reversed, the mean stress will be zero.
σm = 0
Step 2: Calculation of alternating stress (σa)
σa = σ/2 = 250/2 = 125 N/mm²
Step 3: Calculation of stress ratio (R)
As the stress is reversed, the stress ratio will be -1.
R = -1
Step 4: Calculation of modified endurance limit (S'e)
S'e = Se*(1+R)^(1/2) = 101*(1-1)^(1/2) = 0 N/mm²
Step 5: Calculation of fatigue strength parameter (f)
f = σa/S'e = (125/0) = Infinity
Step 6: Calculation of fatigue life (Nf)
Nf = (f)^(-b) = Infinity^(-b) = 0
The fatigue life of the steel bar is zero, which means it will fail after a few cycles. However, the given options suggest that the answer should be between 23800 and 23950 cycles. This implies that there might be an error in the given data or options.
Diameter of forged steel bar (d) = 50 mm
Reversed bending stress (σ) = 250 N/mm²
Steel material = 40 C8 mm (Sut = 600 N/mm²)
Corrected endurance limit (Se) = 101 N/mm²
To find: Life of the steel bar in cycles
Solution:
Step 1: Calculation of mean stress (σm)
As the stress is reversed, the mean stress will be zero.
σm = 0
Step 2: Calculation of alternating stress (σa)
σa = σ/2 = 250/2 = 125 N/mm²
Step 3: Calculation of stress ratio (R)
As the stress is reversed, the stress ratio will be -1.
R = -1
Step 4: Calculation of modified endurance limit (S'e)
S'e = Se*(1+R)^(1/2) = 101*(1-1)^(1/2) = 0 N/mm²
Step 5: Calculation of fatigue strength parameter (f)
f = σa/S'e = (125/0) = Infinity
Step 6: Calculation of fatigue life (Nf)
Nf = (f)^(-b) = Infinity^(-b) = 0
The fatigue life of the steel bar is zero, which means it will fail after a few cycles. However, the given options suggest that the answer should be between 23800 and 23950 cycles. This implies that there might be an error in the given data or options.
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A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.a) 23800b) 23950Correct answer is between ' 23800, 23950'. Can you explain this answer?
Question Description
A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.a) 23800b) 23950Correct answer is between ' 23800, 23950'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.a) 23800b) 23950Correct answer is between ' 23800, 23950'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.a) 23800b) 23950Correct answer is between ' 23800, 23950'. Can you explain this answer?.
A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.a) 23800b) 23950Correct answer is between ' 23800, 23950'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.a) 23800b) 23950Correct answer is between ' 23800, 23950'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A forged steel bar of 50 mm diameter, is subjected to a reversed bending stress of 250N/mm2 . The bar is made of steel 40 C8 mm (Sut = 600 N/mm2)and the corrected endurance limit of the bar is 101N/mm2 , then life of the steel bar will be __________ cycles.a) 23800b) 23950Correct answer is between ' 23800, 23950'. Can you explain this answer?.
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