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A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________
- a)394
- b)396
Correct answer is between ' 394, 396'. Can you explain this answer?
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Verified Answer
A rotating bar of steel (Sut = 600N/mm2) is subjected to a completel...
Given: sut = 630 N/mm2; se = 315 N/mm2
N = 70000 cycles
Now,log10(0.9 Sut) = log10(567) = 2.7536
Log10 (se) = log10(315) = 2.4983
log10(N) = log10(70000) = 4.8451
So, from S-N diagram
x (4.8451 - 3)
log10 (s’f) = 2.5966
S’f = (10)2.5966 = 395 N/mm2
Most Upvoted Answer
A rotating bar of steel (Sut = 600N/mm2) is subjected to a completel...
Given data:
Sut = 600N/mm2
Corrected endurance limit = 315N/mm2
Number of cycles = 70000
To calculate the fatigue strength of the bar, we need to use the S-N curve. The S-N curve is a graphical representation of the relationship between alternating stress (S) and the number of cycles to failure (N) for a material.
Steps to calculate the fatigue strength:
1. Find the stress amplitude:
The stress amplitude is defined as the maximum stress minus the minimum stress. In this case, the stress is completely reversed, so the stress amplitude is equal to the maximum stress.
Stress amplitude = Sut/2 = 600/2 = 300N/mm2
2. Find the fatigue strength coefficient:
The fatigue strength coefficient (b) is a material property that can be found from the S-N curve. For steel, the value of b is typically between 0.05 and 0.15.
Assuming b = 0.1, we can calculate the fatigue strength coefficient as follows:
b = log(Sut/Se') / log(Nf)
0.1 = log(600/315) / log(Nf)
Nf = 10^(log(600/315)/0.1) = 39888 cycles
3. Calculate the fatigue strength:
The fatigue strength (Sf) is the stress level at which the material will withstand a given number of cycles without failing. We can use the following formula to calculate the fatigue strength:
Sf = (b*Nf)^(-1/b) * Se'
Sf = (0.1*39888)^(-1/0.1) * 315 = 395.8N/mm2
Therefore, the fatigue strength of the bar for a life of 70000 cycles is approximately 396N/mm2.
Sut = 600N/mm2
Corrected endurance limit = 315N/mm2
Number of cycles = 70000
To calculate the fatigue strength of the bar, we need to use the S-N curve. The S-N curve is a graphical representation of the relationship between alternating stress (S) and the number of cycles to failure (N) for a material.
Steps to calculate the fatigue strength:
1. Find the stress amplitude:
The stress amplitude is defined as the maximum stress minus the minimum stress. In this case, the stress is completely reversed, so the stress amplitude is equal to the maximum stress.
Stress amplitude = Sut/2 = 600/2 = 300N/mm2
2. Find the fatigue strength coefficient:
The fatigue strength coefficient (b) is a material property that can be found from the S-N curve. For steel, the value of b is typically between 0.05 and 0.15.
Assuming b = 0.1, we can calculate the fatigue strength coefficient as follows:
b = log(Sut/Se') / log(Nf)
0.1 = log(600/315) / log(Nf)
Nf = 10^(log(600/315)/0.1) = 39888 cycles
3. Calculate the fatigue strength:
The fatigue strength (Sf) is the stress level at which the material will withstand a given number of cycles without failing. We can use the following formula to calculate the fatigue strength:
Sf = (b*Nf)^(-1/b) * Se'
Sf = (0.1*39888)^(-1/0.1) * 315 = 395.8N/mm2
Therefore, the fatigue strength of the bar for a life of 70000 cycles is approximately 396N/mm2.
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A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________a) 394b) 396Correct answer is between ' 394, 396'. Can you explain this answer?
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A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________a) 394b) 396Correct answer is between ' 394, 396'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________a) 394b) 396Correct answer is between ' 394, 396'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________a) 394b) 396Correct answer is between ' 394, 396'. Can you explain this answer?.
A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________a) 394b) 396Correct answer is between ' 394, 396'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________a) 394b) 396Correct answer is between ' 394, 396'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rotating bar of steel (Sut = 600N/mm2) is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 315N/mm2 . The fatigue strength (in N/mm2) of the bar for a life of 70000 cycles is __________a) 394b) 396Correct answer is between ' 394, 396'. Can you explain this answer?.
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