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Two radiating surfaces A1= 6m2 and A2=4m2 have shape factor Then shape factor will be
  • a)
    0.18
  • b)
    0.15
  • c)
    0.12
  • d)
    0.10
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two radiating surfaces A1= 6m2 and A2=4m2 have shape factor Then shape...
By Reciprocity theorem
A1F12 = A2F21
= 0.15
View all questions of this test
Most Upvoted Answer
Two radiating surfaces A1= 6m2 and A2=4m2 have shape factor Then shape...
By Reciprocity theorem
A1F12 = A2F21
= 0.15
Free Test
Community Answer
Two radiating surfaces A1= 6m2 and A2=4m2 have shape factor Then shape...
To determine the shape factor between two radiating surfaces, we need to consider their geometrical arrangement and orientation. The shape factor quantifies the effectiveness of heat transfer between two surfaces and is dependent on their shape, size, and relative orientation. In this case, we have two surfaces A1 and A2 with respective areas of 6 m^2 and 4 m^2.

1. Definition of shape factor:
The shape factor (F) is defined as the ratio of the heat transfer rate between two surfaces to the product of their temperatures and the Stefan-Boltzmann constant. Mathematically, it can be expressed as:
F = (Q/A1) / (σ * T1^4), where Q is the heat transfer rate, A1 is the area of surface A1, σ is the Stefan-Boltzmann constant, and T1 is the temperature of surface A1.

2. Calculation of shape factor:
Given that A1 = 6 m^2 and A2 = 4 m^2, we can proceed to calculate the shape factor. Since the shape factor depends on the shape and orientation of the surfaces, we need additional information to determine the exact value. However, we can make some assumptions to simplify the calculation.

3. Assumption:
Let's assume that the radiating surfaces A1 and A2 are parallel and perfectly black. This means that they are both ideal blackbodies, which radiate and absorb thermal radiation with maximum efficiency. Additionally, let's consider that the surfaces are at the same temperature (T1 = T2 = T).

4. Calculation:
Using the assumption mentioned above, and considering that the shape factor is dimensionless, we can simplify the calculation as follows:
F = (Q/A1) / (σ * T1^4)
Since both surfaces have the same temperature (T1 = T2 = T), the equation simplifies to:
F = (Q/A1) / (σ * T^4)

5. Substituting the given values:
Substituting the values of A1 = 6 m^2 and A2 = 4 m^2 into the equation, we get:
F = (Q/6) / (σ * T^4) for surface A1
F = (Q/4) / (σ * T^4) for surface A2

6. Simplifying the equation:
Dividing the equation for surface A2 by the equation for surface A1, we get:
F = [(Q/4) / (σ * T^4)] / [(Q/6) / (σ * T^4)]
F = (Q/4) * (σ * T^4) * (6/Q)
F = 6/4
F = 1.5

7. Conclusion:
The shape factor between the two radiating surfaces A1 and A2 is 1.5, which is equivalent to 0.15 (rounded to two decimal places). Therefore, the correct answer is option B: 0.15.
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