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Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Vapour pressure of a solvent is the pressure exerted by vapours when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent on nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate.The vapurpressuere ofa mixture obtained by mixing two volatile liquids is given by PM = . XA + . XBwhereandare vapour pressures of pure components A and B and XA, XBare their mole fraction in mixture . For solute-solvent system, the realtion become PM = . XAwhere B is non-volatile solute.Q. The amount of solute (mol. wt. 60) required to dissolve in 180 g of water to reduce the vapour pressure to 4/5 of the pure water -a)120 gb)150 gc)200 gd)60 gCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.