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A man buys two horse for 1350 he sells one so as lose 6%and the other so as to gain 7.5% on the whole he neither gains nor loses what does each horse cost?
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A man buys two horse for 1350 he sells one so as lose 6%and the other ...
Problem: A man buys two horse for 1350 he sells one so as lose 6% and the other so as to gain 7.5%. On the whole, he neither gains nor loses. What does each horse cost?

Solution:

Let the cost of the first horse be x, and the cost of the second horse be y.

We know that x + y = 1350 ----(1)

Also, the man sells one horse at a loss of 6% and the other at a profit of 7.5%.

The selling price of the first horse is (1-6/100)x = 0.94x
The selling price of the second horse is (1+7.5/100)y = 1.075y

Since the man neither gains nor loses, the total selling price must be equal to the total cost price.

0.94x + 1.075y = 1350 ----(2)

Now, we have two equations (1) and (2) with two unknowns x and y. We can solve these equations to find the values of x and y.

Multiplying equation (1) by 0.94, we get:

0.94x + 0.94y = 1269 ----(3)

Subtracting equation (3) from equation (2), we get:

0.135y = 81

y = 600

Substituting the value of y in equation (1), we get:

x + 600 = 1350

x = 750

Therefore, the cost of the first horse is 750 and the cost of the second horse is 600.

Answer: The cost of the first horse is 750 and the cost of the second horse is 600.
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A man buys two horse for 1350 he sells one so as lose 6%and the other ...
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