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A steady, incompressible, two–dimensional velocity field is given by V‾ = (u, v) = (0.5 + 0.8x)î + (1.5 − 0.8 y)ĵ The number of stagnation points in the flow field is
- a)zero
- b)many
- c)1
- d)2
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A steady, incompressible, two–dimensional velocity field is given by ...
Stagnation points are those points where (u, v) = 0
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u = 0.5 + 0.8x = 0
∴ x = −0.5 / 0.8 = −0.625
v = 1.5 − 0.8y = 0
∴ y = 1.5 / 0.8 = 1.875
i.e there is only one stagnation point at (−0.625, 1.875)
Most Upvoted Answer
A steady, incompressible, two–dimensional velocity field is given by ...
Given information:
The velocity field is given by V‾ = (u, v) = (0.5 0.8x)î (1.5 − 0.8 y)ĵ
Explanation:
To determine the number of stagnation points in the flow field, we need to find the points where the velocity vector becomes zero.
Step 1: Find the x-coordinate of the stagnation point(s)
Setting the x-component of the velocity vector to zero:
0.5 + 0.8x = 0
0.8x = -0.5
x = -0.5/0.8
x = -0.625
Step 2: Find the y-coordinate of the stagnation point(s)
Setting the y-component of the velocity vector to zero:
1.5 - 0.8y = 0
0.8y = 1.5
y = 1.5/0.8
y = 1.875
Step 3: Determine the number of stagnation points
From the above calculations, we find that there is only one point where the velocity vector becomes zero, which is at (-0.625, 1.875).
Therefore, the number of stagnation points in the flow field is 1.
Answer:
The correct answer is option C) 1.
The velocity field is given by V‾ = (u, v) = (0.5 0.8x)î (1.5 − 0.8 y)ĵ
Explanation:
To determine the number of stagnation points in the flow field, we need to find the points where the velocity vector becomes zero.
Step 1: Find the x-coordinate of the stagnation point(s)
Setting the x-component of the velocity vector to zero:
0.5 + 0.8x = 0
0.8x = -0.5
x = -0.5/0.8
x = -0.625
Step 2: Find the y-coordinate of the stagnation point(s)
Setting the y-component of the velocity vector to zero:
1.5 - 0.8y = 0
0.8y = 1.5
y = 1.5/0.8
y = 1.875
Step 3: Determine the number of stagnation points
From the above calculations, we find that there is only one point where the velocity vector becomes zero, which is at (-0.625, 1.875).
Therefore, the number of stagnation points in the flow field is 1.
Answer:
The correct answer is option C) 1.
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