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A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is
[2015]
- a)2.5
- b)5.0
- c)7.5
- d)10.0
Correct answer is option 'B'. Can you explain this answer?
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A resistance-capacitance relaxation circuit is used in an electrical d...
where:
V = Voltage
t= time
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A resistance-capacitance relaxation circuit is used in an electrical d...
Given data:
Discharge voltage (V) = 100 V
Spark cycle time (t) = 25 ms = 0.025 s
Average power input (P) = 1 kW = 1000 W
Assuming the resistance-capacitance (RC) circuit to be a series circuit, the power input to the circuit can be given by the formula:
P = V^2 / R …(1)
where R is the resistance of the circuit.
The time constant (τ) of the circuit can be given by the formula:
τ = RC …(2)
The spark cycle time (t) is given by:
t = 5τ …(3)
Substituting equation (2) in (3), we get:
t = 5RC
Solving equation (1) for R, we get:
R = V^2 / P
Substituting this value of R in equation (2), we get:
τ = C(V^2 / P)
Substituting this value of τ in equation (3), we get:
t = 5C(V^2 / P)
Solving for C, we get:
C = (tP) / (5V^2)
Substituting the given values, we get:
C = (0.025 x 1000) / (5 x 100^2) = 0.005 = 5 mF
Therefore, the capacitance (in mF) in the circuit is 5.0 (option B).
Discharge voltage (V) = 100 V
Spark cycle time (t) = 25 ms = 0.025 s
Average power input (P) = 1 kW = 1000 W
Assuming the resistance-capacitance (RC) circuit to be a series circuit, the power input to the circuit can be given by the formula:
P = V^2 / R …(1)
where R is the resistance of the circuit.
The time constant (τ) of the circuit can be given by the formula:
τ = RC …(2)
The spark cycle time (t) is given by:
t = 5τ …(3)
Substituting equation (2) in (3), we get:
t = 5RC
Solving equation (1) for R, we get:
R = V^2 / P
Substituting this value of R in equation (2), we get:
τ = C(V^2 / P)
Substituting this value of τ in equation (3), we get:
t = 5C(V^2 / P)
Solving for C, we get:
C = (tP) / (5V^2)
Substituting the given values, we get:
C = (0.025 x 1000) / (5 x 100^2) = 0.005 = 5 mF
Therefore, the capacitance (in mF) in the circuit is 5.0 (option B).
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A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is[2015]a)2.5b)5.0c)7.5d)10.0Correct answer is option 'B'. Can you explain this answer?
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A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is[2015]a)2.5b)5.0c)7.5d)10.0Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is[2015]a)2.5b)5.0c)7.5d)10.0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is[2015]a)2.5b)5.0c)7.5d)10.0Correct answer is option 'B'. Can you explain this answer?.
A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is[2015]a)2.5b)5.0c)7.5d)10.0Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is[2015]a)2.5b)5.0c)7.5d)10.0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistance-capacitance relaxation circuit is used in an electrical discharge machining process. The discharge voltage is 100 V. At a spark cycle time of 25 ms, the average power input required is 1 kW. The capacitance (in mF) in the circuit is[2015]a)2.5b)5.0c)7.5d)10.0Correct answer is option 'B'. Can you explain this answer?.
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