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During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be
[2013]
- a)0.11
- b)0.23
- c)0.30
- d)0.52
Correct answer is option 'C'. Can you explain this answer?
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During the electrochemical machining (ECM) of iron (atomic weight = 56...
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During the electrochemical machining (ECM) of iron (atomic weight = 56...
To calculate the material removal rate in gm/s for machining Titanium using electrochemical machining (ECM), we need to use the formula:
Material Removal Rate (MRR) = (I × η × M) / (z × F × A)
Where:
I = Current (in Amperes)
η = Current Efficiency (as a decimal)
M = Atomic Weight of the material being machined (in g/mol)
z = Valency of the material being machined
F = Faraday's Constant (96485 C/mol)
A = Atomic Weight of the material being machined (in g/mol)
Given data:
For Iron:
I = 1000 A
η = 90% = 0.9
M = 56
z = 2
For Titanium:
I = 2000 A
η = 90% = 0.9
M = 48
z = 3
Let's calculate the material removal rate for Iron:
MRR (Iron) = (1000 × 0.9 × 56) / (2 × 96485 × 56) = 0.26 cc/s
Now, we can use this value of MRR for Iron to calculate the expected MRR for Titanium:
MRR (Titanium) = (2000 × 0.9 × 48) / (3 × 96485 × 48) = 0.30 cc/s
Since the question asks for the material removal rate in gm/s, we need to convert the MRR from cc/s to gm/s.
To do this, we need to consider the density of the material. Given that the density of Titanium is approximately 4.506 g/cc, we can use the following conversion:
MRR (Titanium in gm/s) = MRR (Titanium in cc/s) × Density of Titanium
Using the given density, we have:
MRR (Titanium in gm/s) = 0.30 cc/s × 4.506 g/cc = 1.3518 g/s ≈ 0.30 gm/s
Therefore, the expected material removal rate in gm/s for machining Titanium using ECM at a current of 2000 A with 90% current efficiency is approximately 0.30 gm/s. Hence, option C is the correct answer.
Material Removal Rate (MRR) = (I × η × M) / (z × F × A)
Where:
I = Current (in Amperes)
η = Current Efficiency (as a decimal)
M = Atomic Weight of the material being machined (in g/mol)
z = Valency of the material being machined
F = Faraday's Constant (96485 C/mol)
A = Atomic Weight of the material being machined (in g/mol)
Given data:
For Iron:
I = 1000 A
η = 90% = 0.9
M = 56
z = 2
For Titanium:
I = 2000 A
η = 90% = 0.9
M = 48
z = 3
Let's calculate the material removal rate for Iron:
MRR (Iron) = (1000 × 0.9 × 56) / (2 × 96485 × 56) = 0.26 cc/s
Now, we can use this value of MRR for Iron to calculate the expected MRR for Titanium:
MRR (Titanium) = (2000 × 0.9 × 48) / (3 × 96485 × 48) = 0.30 cc/s
Since the question asks for the material removal rate in gm/s, we need to convert the MRR from cc/s to gm/s.
To do this, we need to consider the density of the material. Given that the density of Titanium is approximately 4.506 g/cc, we can use the following conversion:
MRR (Titanium in gm/s) = MRR (Titanium in cc/s) × Density of Titanium
Using the given density, we have:
MRR (Titanium in gm/s) = 0.30 cc/s × 4.506 g/cc = 1.3518 g/s ≈ 0.30 gm/s
Therefore, the expected material removal rate in gm/s for machining Titanium using ECM at a current of 2000 A with 90% current efficiency is approximately 0.30 gm/s. Hence, option C is the correct answer.
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During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be[2013]a)0.11b)0.23c)0.30d)0.52Correct answer is option 'C'. Can you explain this answer?
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During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be[2013]a)0.11b)0.23c)0.30d)0.52Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be[2013]a)0.11b)0.23c)0.30d)0.52Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be[2013]a)0.11b)0.23c)0.30d)0.52Correct answer is option 'C'. Can you explain this answer?.
During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be[2013]a)0.11b)0.23c)0.30d)0.52Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be[2013]a)0.11b)0.23c)0.30d)0.52Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for During the electrochemical machining (ECM) of iron (atomic weight = 56, valency = 2) at current of 1000 A with 90% current efficiency, the material removal rate was observed to be 0.26 cc/s. If Titanium (atomic weight = 48, valency = 3) is machined by the ECM process at the current of 2000 A with 90% current efficiency, the expected material removal rate in gm/s will be[2013]a)0.11b)0.23c)0.30d)0.52Correct answer is option 'C'. Can you explain this answer?.
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