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Electrochemical machining is performed to remove material from an iron surface of 20 mm × 20 mm under the following conditions: Inter electrode gap = 0.2 mm Supply voltage (DC) = 12 V Specific resistance of electrolyte = 2 ohm- cm Atomic weight of iron = 55.85 Valency of Iron = 2 Faraday's constant = 96540 Coulombs The material removal rate (in g/s) is
[2009]
  • a)
    0.3471
  • b)
    3.471
  • c)
    34.71
  • d)
    347.1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Electrochemical machining is performed to remove material from an iron...
We know , 
where,
p= resistivity
= special resistance of electrolyte 
= 2Ω
R = resistance of electrolyte between electron
l= interelectrode gap = 0.2 mm
A = electrodes cross sectional area = 20x20 
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Most Upvoted Answer
Electrochemical machining is performed to remove material from an iron...
Thickness. The process uses a voltage of 10 V and a current of 5 A. The machining time is 30 minutes. Assuming an efficiency of 80%, calculate:

a) The amount of material removed.

b) The energy consumed during the process.

c) The cost of the process, assuming an energy cost of $0.10 per kWh.

Solution:

a) The amount of material removed is given by:

M = I*t*E/(Z*η)

Where:

I = current = 5 A
t = time = 30 minutes = 0.5 hours
E = voltage = 10 V
Z = atomic weight of iron = 55.85 g/mol
η = efficiency = 0.8

Substituting the values, we get:

M = 5*0.5*10/(55.85*0.8) = 0.57 g

Therefore, the amount of material removed is 0.57 g.

b) The energy consumed during the process is given by:

E = P*t

Where:

P = power = V*I = 10*5 = 50 W
t = time = 30 minutes = 0.5 hours

Substituting the values, we get:

E = 50*0.5 = 25 Wh = 0.025 kWh

Therefore, the energy consumed during the process is 0.025 kWh.

c) The cost of the process is given by:

Cost = E*cost per kWh

Where:

E = energy consumed = 0.025 kWh
Cost per kWh = $0.10

Substituting the values, we get:

Cost = 0.025*0.10 = $0.0025

Therefore, the cost of the process is $0.0025.
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Electrochemical machining is performed to remove material from an iron surface of 20 mm × 20 mm under the following conditions: Inter electrode gap = 0.2 mm Supply voltage (DC) = 12 V Specific resistance of electrolyte = 2 ohm- cm Atomic weight of iron = 55.85 Valency of Iron = 2 Faradays constant = 96540 Coulombs The material removal rate (in g/s) is[2009]a)0.3471b)3.471c)34.71d)347.1Correct answer is option 'A'. Can you explain this answer?
Question Description
Electrochemical machining is performed to remove material from an iron surface of 20 mm × 20 mm under the following conditions: Inter electrode gap = 0.2 mm Supply voltage (DC) = 12 V Specific resistance of electrolyte = 2 ohm- cm Atomic weight of iron = 55.85 Valency of Iron = 2 Faradays constant = 96540 Coulombs The material removal rate (in g/s) is[2009]a)0.3471b)3.471c)34.71d)347.1Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Electrochemical machining is performed to remove material from an iron surface of 20 mm × 20 mm under the following conditions: Inter electrode gap = 0.2 mm Supply voltage (DC) = 12 V Specific resistance of electrolyte = 2 ohm- cm Atomic weight of iron = 55.85 Valency of Iron = 2 Faradays constant = 96540 Coulombs The material removal rate (in g/s) is[2009]a)0.3471b)3.471c)34.71d)347.1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electrochemical machining is performed to remove material from an iron surface of 20 mm × 20 mm under the following conditions: Inter electrode gap = 0.2 mm Supply voltage (DC) = 12 V Specific resistance of electrolyte = 2 ohm- cm Atomic weight of iron = 55.85 Valency of Iron = 2 Faradays constant = 96540 Coulombs The material removal rate (in g/s) is[2009]a)0.3471b)3.471c)34.71d)347.1Correct answer is option 'A'. Can you explain this answer?.
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