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Consider steady-state heat conduction across the thickness in a plane composite wall (as shown in the figure) exposed to convection conditions on both sides. Given: hi = 20 W/m2K; h0 = 50 W/m2K; T∝i = 20°C; T∝,0 = -2°C; k1 = 20 W/mK; k2 = 50 W/mK; L1 = 0.30 m and L2 = 0.15 m. Assuming negligible contact resistance between the wall surfaces, the interface termperature, T(in °C), of the two walls will be
[2009]
  • a)
    -0.50
  • b)
    2.75
  • c)
    3.75
  • d)
    4.50
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider steady-state heat conduction across the thickness in a plane ...


Now 
∴ 
⇒ 
⇒ t = 3.75 °C
Alternately
Under steady state conditions

∴ 
or 
or 
or 20 – ti = 2.826 (ti + 2)
or 3.826 ti = 20 – 2 x 2.826
or ti = 3.75°C
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Most Upvoted Answer
Consider steady-state heat conduction across the thickness in a plane ...


Now 
∴ 
⇒ 
⇒ t = 3.75 °C
Alternately
Under steady state conditions

∴ 
or 
or 
or 20 – ti = 2.826 (ti + 2)
or 3.826 ti = 20 – 2 x 2.826
or ti = 3.75°C
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Consider steady-state heat conduction across the thickness in a plane composite wall (as shown in the figure) exposed to convection conditions on both sides. Given: hi = 20 W/m2K; h0 = 50 W/m2K; T∝i = 20°C; T∝,0 = -2°C; k1 = 20 W/mK; k2 = 50 W/mK; L1 = 0.30 m and L2 = 0.15 m. Assuming negligible contact resistance between the wall surfaces, the interface termperature, T(in °C), of the two walls will be[2009]a)-0.50b)2.75c)3.75d)4.50Correct answer is option 'C'. Can you explain this answer?
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