Class 11 Exam > Class 11 Questions > A solution of oxalic acid, (COOH)2.2H2O is pr...
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A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)?
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A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's...
Given:
- Mass of oxalic acid, (COOH)2.2H2O = 4g
- Volume of solution = 250ml
To find:
- Molarity of the solution
Formula:
Molarity (M) = Number of moles of solute/Volume of solution (in liters)
Step-by-step solution:
Step 1: Find the molar mass of oxalic acid, (COOH)2.2H2O
- The molar mass of carbon (C) = 12g/mol
- The molar mass of oxygen (O) = 16g/mol
- The molar mass of hydrogen (H) = 1g/mol
The molar mass of oxalic acid, (COOH)2.2H2O
= (2 x Molar mass of carbon) + (4 x Molar mass of oxygen) + (4 x Molar mass of hydrogen)
= (2 x 12) + (4 x 16) + (4 x 1)
= 24 + 64 + 4
= 92g/mol
Step 2: Calculate the number of moles of oxalic acid
Number of moles = Mass of solute/Molar mass
Number of moles = 4g/92g/mol
Number of moles = 0.04348 mol
Step 3: Convert the volume of solution to liters
Volume of solution = 250ml = 250/1000 = 0.25L
Step 4: Calculate the molarity of the solution
Molarity (M) = Number of moles/Volume of solution (in liters)
Molarity (M) = 0.04348 mol/0.25L
Molarity (M) = 0.17392 M
Answer:
The molarity of the oxalic acid solution is 0.17392 M.
- Mass of oxalic acid, (COOH)2.2H2O = 4g
- Volume of solution = 250ml
To find:
- Molarity of the solution
Formula:
Molarity (M) = Number of moles of solute/Volume of solution (in liters)
Step-by-step solution:
Step 1: Find the molar mass of oxalic acid, (COOH)2.2H2O
- The molar mass of carbon (C) = 12g/mol
- The molar mass of oxygen (O) = 16g/mol
- The molar mass of hydrogen (H) = 1g/mol
The molar mass of oxalic acid, (COOH)2.2H2O
= (2 x Molar mass of carbon) + (4 x Molar mass of oxygen) + (4 x Molar mass of hydrogen)
= (2 x 12) + (4 x 16) + (4 x 1)
= 24 + 64 + 4
= 92g/mol
Step 2: Calculate the number of moles of oxalic acid
Number of moles = Mass of solute/Molar mass
Number of moles = 4g/92g/mol
Number of moles = 0.04348 mol
Step 3: Convert the volume of solution to liters
Volume of solution = 250ml = 250/1000 = 0.25L
Step 4: Calculate the molarity of the solution
Molarity (M) = Number of moles/Volume of solution (in liters)
Molarity (M) = 0.04348 mol/0.25L
Molarity (M) = 0.17392 M
Answer:
The molarity of the oxalic acid solution is 0.17392 M.
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A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)?
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A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)?.
A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of oxalic acid, (COOH)2.2H2O is prepared by dissolving it's 4g in enough water to form 250ml of the solution. Calculate it's molarity. (At. Mass of C=12u; O=6u; H=1u)?.
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