A closed cubical box pointed metre on his side is half filled with wat...
Problem Statement: A closed cubical box pointed metre on his side is half filled with water and other half being the field with oil of specific gravity point 75 then the pressure difference at the bottom and top player in past? Explain in details.
Solution:
Given,
- The cubical box is pointed metre on his side.
- The box is half filled with water and half filled with oil of specific gravity 0.75.
We need to find the pressure difference at the bottom and top layer.
Calculation:
1. Pressure due to water:
- Density of water, ρw = 1000 kg/m³
- Height of water column, h = 0.5 m (as the box is half filled with water)
- Acceleration due to gravity, g = 9.8 m/s²
- Pressure due to water, Pw = ρw * g * h
Pw = 1000 * 9.8 * 0.5
Pw = 4900 Pa
2. Pressure due to oil:
- Density of oil, ρo = 0.75 * 1000 = 750 kg/m³ (as the specific gravity of oil is 0.75)
- Height of oil column, h = 0.5 m (as the box is half filled with oil)
- Acceleration due to gravity, g = 9.8 m/s²
- Pressure due to oil, Po = ρo * g * h
Po = 750 * 9.8 * 0.5
Po = 3675 Pa
3. Total pressure difference:
- Pressure difference between the bottom and top layers of the box, P = Pw - Po
P = 4900 - 3675
P = 1225 Pa
Therefore, the pressure difference at the bottom and top layers of the box is 1225 Pa.
Conclusion: The pressure difference at the bottom and top layers of the box is 1225 Pa due to the difference in the densities of water and oil present in the box.