A man leaves his home and walks at a speed of 12 km per hour, reaching the railway station 10 minutes after the train had departed. If instead he had walked at a speed of 15 km per hour, he would have reached the station 10 minutes before the trains departure. The distance (in km) from his home to the railway station isCorrect answer is '20'. Can you explain this answer?

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A man leaves his home and walks at a speed of 12 km per hour, reaching the railway station 10 minutes after the train had departed. If instead he had walked at a speed of 15 km per hour, he would have reached the station 10 minutes before the train's departure. The distance (in km) from his home to the railway station is

Correct answer is '20'. Can you explain this answer?

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A man leaves his home and walks at a speed of 12 km per hour, reaching...

We see that the man saves 20 minutes by changing his speed from 12 Km/hr to 15 Km/hr. Let d be the distance

Hence,

d/12 – d/15 = 1/3

d/60 = 1/3

d = 20 Km.

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Most Upvoted Answer

A man leaves his home and walks at a speed of 12 km per hour, reaching...

We see that the man saves 20 minutes by changing his speed from 12 Km/hr to 15 Km/hr. Let d be the distance

Hence,

d/12 – d/15 = 1/3

d/60 = 1/3

d = 20 Km.

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A man leaves his home and walks at a speed of 12 km per hour, reaching...

Given Information:
- The man walks at a speed of 12 km per hour.
- He reaches the railway station 10 minutes after the train had departed.
- If he had walked at a speed of 15 km per hour, he would have reached the station 10 minutes before the train's departure.

To Find:
The distance (in km) from his home to the railway station.

Assumptions:
- The train's speed and the time it takes to travel from the man's home to the railway station are constant.
- The time mentioned in the problem is in minutes.

Solution:
Let's assume the distance from the man's home to the railway station is 'd' km.

Case 1: Walking at a speed of 12 km/hr
- Time taken to reach the railway station = (d/12) hours
- The man reaches 10 minutes after the train had departed, so the time taken by the train to travel the distance 'd' is (d/12) + (10/60) hours.

Case 2: Walking at a speed of 15 km/hr
- Time taken to reach the railway station = (d/15) hours
- The man would have reached 10 minutes before the train's departure, so the time taken by the train to travel the distance 'd' is (d/15) - (10/60) hours.

Since the distance is the same in both cases, we can equate the expressions for the time taken by the train:
(d/12) + (10/60) = (d/15) - (10/60)

Simplifying the equation:
- Multiplying both sides by 60 to eliminate the denominators: 5d + 10 = 4d - 10
- Simplifying: d = 20

Therefore, the distance from the man's home to the railway station is 20 km.

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A man leaves his home and walks at a speed of 12 km per hour, reaching the railway station 10 minutes after the train had departed. If instead he had walked at a speed of 15 km per hour, he would have reached the station 10 minutes before the trains departure. The distance (in km) from his home to the railway station is Correct answer is '20'. Can you explain this answer?

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A man leaves his home and walks at a speed of 12 km per hour, reaching the railway station 10 minutes after the train had departed. If instead he had walked at a speed of 15 km per hour, he would have reached the station 10 minutes before the trains departure. The distance (in km) from his home to the railway station isCorrect answer is '20'. Can you explain this answer?

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