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For gas welding a particular job using a neutral oxyacetylene flame the acetylene consumption was 10 litres. The oxygen consumption from the cylinder in liters will be
[ME 1991]
  • a)
    5
  • b)
    10
  • c)
    15
  • d)
    20
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For gas welding a particular job using a neutral oxyacetylene flame th...
In neutral flame, volume of both oxygen and acetylene are equal.
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Most Upvoted Answer
For gas welding a particular job using a neutral oxyacetylene flame th...
To understand why the oxygen consumption from the cylinder is 10 liters, we need to understand the stoichiometry of the oxyacetylene flame and the gas ratio used in gas welding.

**Oxyacetylene Flame Stoichiometry:**

The oxyacetylene flame is created by mixing acetylene (C2H2) and oxygen (O2) in the correct proportion. The ideal ratio for a neutral flame, which is commonly used in gas welding, is 1:1.2. This means that for every 1 part of acetylene, we need 1.2 parts of oxygen.

**Gas Ratio:**

The gas ratio is the ratio of acetylene to oxygen used in the welding process. In this case, the gas ratio is 1:1.2, which means that for every liter of acetylene consumed, we need 1.2 liters of oxygen.

**Acetylene Consumption:**

Given that the acetylene consumption is 10 liters, we can calculate the oxygen consumption using the gas ratio.

Oxygen Consumption = Acetylene Consumption * Gas Ratio
= 10 * 1.2
= 12 liters

Therefore, the oxygen consumption from the cylinder is 12 liters.

However, in the options provided, the closest value to 12 liters is 10 liters, which is option 'B'. This may indicate a typographical error in the options, or the question may have been designed with a different gas ratio in mind.

In any case, based on the gas ratio of 1:1.2 for a neutral oxyacetylene flame, the correct answer should be 12 liters for the oxygen consumption.
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For gas welding a particular job using a neutral oxyacetylene flame the acetylene consumption was 10 litres. The oxygen consumption from the cylinder in liters will be[ME 1991]a)5b)10c)15d)20Correct answer is option 'B'. Can you explain this answer?
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