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Autogeneous gas tungsten arc welding of a steel plate is carried out with welding current of 500 A. Voltage of 20 V and weld speed of 20 mm/ min. Consider the heat transfer efficiency from the arc to the weld pool as 90%. The heat input per unit length (in kJ/mm) is
[PI 2009]
  • a)
    27
  • b)
    35
  • c)
    45
  • d)
    55
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Autogeneous gas tungsten arc welding of a steel plate is carried out w...
Current = 500 A
Voltage = 20 V
V = 20 mm/min
ηHT= 0.9

= 27 kJ/mm
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Most Upvoted Answer
Autogeneous gas tungsten arc welding of a steel plate is carried out w...
Heat input is an important parameter in welding processes as it determines the amount of heat energy transferred to the weld pool. Heat input per unit length is calculated by multiplying the welding current, voltage, and the heat transfer efficiency.

Given:
Welding current (I) = 500 A
Voltage (V) = 20 V
Weld speed (W) = 20 mm/min
Heat transfer efficiency (η) = 90%

To calculate the heat input per unit length, we need to convert the weld speed from mm/min to mm/sec.

Weld speed (W) = 20 mm/min = (20 mm/min) * (1 min/60 sec) = 0.33 mm/sec

The formula to calculate heat input per unit length (HI) is:
HI = (I * V) / (W * η)

Substituting the given values into the formula, we get:
HI = (500 A * 20 V) / (0.33 mm/sec * 90%)

Simplifying the equation, we have:
HI = (10,000 VA) / (0.33 mm/sec * 0.9)

HI = 10,000 / (0.297 mm/sec)

HI ≈ 33,670.03 kJ/mm

The heat input per unit length is approximately 33,670.03 kJ/mm.

Therefore, the correct answer is option 'A' - 27 kJ/mm.

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Autogeneous gas tungsten arc welding of a steel plate is carried out with welding current of 500 A. Voltage of 20 V and weld speed of 20 mm/ min. Consider the heat transfer efficiency from the arc to the weld pool as 90%. The heat input per unit length (in kJ/mm) is[PI 2009]a)27b)35c)45d)55Correct answer is option 'A'. Can you explain this answer?
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