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Given an equilateral triangle T1 with side 24 cm, a second triangle T2 is formed by joining the midpoints of the sides of T1. Then a third triangle T3 is formed by joining the midpoints of the sides of T2. If this process of forming triangles is continued, the sum of the areas, in sq cm, of infinitely many such triangles T1, T2, T3,... will be
(2018)
  • a)
    248√3
  • b)
    192√3
  • c)
    188√3
  • d)
    1164√3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Given an equilateral triangle T1 with side 24 cm, a second triangle T2...
An equilateral triangle formed by joining the midpoints of the sides of a given equilateral triangle will have its side equal to half the side of the given equilateral triangle.
Now, side of T1 = 24 cm
Side of T2 = 12 cm
Side of T3 = 6 cm
and so on.
Sum of the areas of all the triangles =
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Most Upvoted Answer
Given an equilateral triangle T1 with side 24 cm, a second triangle T2...
An equilateral triangle formed by joining the midpoints of the sides of a given equilateral triangle will have its side equal to half the side of the given equilateral triangle.
Now, side of T1 = 24 cm
Side of T2 = 12 cm
Side of T3 = 6 cm
and so on.
Sum of the areas of all the triangles =
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Given an equilateral triangle T1 with side 24 cm, a second triangle T2 is formed by joining the midpoints of the sides of T1. Then a third triangle T3 is formed by joining the midpoints of the sides of T2. If this process of forming triangles is continued, the sum of the areas, in sq cm, of infinitely many such triangles T1, T2, T3,... will be(2018)a)248√3b)192√3c)188√3d)1164√3Correct answer is option 'B'. Can you explain this answer?
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