Mechanical Engineering Exam > Mechanical Engineering Questions > For 50% penetration of work material, a punch...
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For 50% penetration of work material, a punch with single shear equal to thickness will
[PI 2001]
- a)reduce the punch load to half the value
- b)increase the punch load by half the value
- c)maintain the same punch load
- d)reduce the punch load to quarter load
Correct answer is option 'A'. Can you explain this answer?
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Explanation:
When a punch is used to make a hole in a workpiece, the material around the hole experiences a certain amount of deformation. This deformation is due to the shear stress in the material caused by the punch. The amount of deformation depends on the penetration of the punch into the material.
For 50% penetration of work material, a punch with single shear equal to thickness will reduce the punch load to half the value. This can be explained as follows:
- Punch load: The punch load is the force required to push the punch through the workpiece. It is directly proportional to the shear stress in the material.
- Single shear: When a punch is used to make a hole, it causes the material around the hole to experience shear stress. This is called single shear because the stress acts on a single plane.
- Penetration: The penetration of the punch into the material is the distance the punch travels before it comes out on the other side.
- 50% penetration: When the punch penetrates the material by 50%, it means that it has travelled half the distance of the thickness of the material.
- Equal to thickness: If the single shear of the punch is equal to the thickness of the material, it means that the punch has the same cross-sectional area as the material around the hole.
- Punch load reduced: When the punch is used to make a hole in the material with 50% penetration and single shear equal to thickness, the punch load is reduced to half the value. This is because the deformation of the material around the hole is reduced due to the equal cross-sectional area of the punch and the material.
Conclusion:
Hence, the correct answer is option 'A' - reduce the punch load to half the value.
When a punch is used to make a hole in a workpiece, the material around the hole experiences a certain amount of deformation. This deformation is due to the shear stress in the material caused by the punch. The amount of deformation depends on the penetration of the punch into the material.
For 50% penetration of work material, a punch with single shear equal to thickness will reduce the punch load to half the value. This can be explained as follows:
- Punch load: The punch load is the force required to push the punch through the workpiece. It is directly proportional to the shear stress in the material.
- Single shear: When a punch is used to make a hole, it causes the material around the hole to experience shear stress. This is called single shear because the stress acts on a single plane.
- Penetration: The penetration of the punch into the material is the distance the punch travels before it comes out on the other side.
- 50% penetration: When the punch penetrates the material by 50%, it means that it has travelled half the distance of the thickness of the material.
- Equal to thickness: If the single shear of the punch is equal to the thickness of the material, it means that the punch has the same cross-sectional area as the material around the hole.
- Punch load reduced: When the punch is used to make a hole in the material with 50% penetration and single shear equal to thickness, the punch load is reduced to half the value. This is because the deformation of the material around the hole is reduced due to the equal cross-sectional area of the punch and the material.
Conclusion:
Hence, the correct answer is option 'A' - reduce the punch load to half the value.
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For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer?.
For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer?.
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For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of For 50% penetration of work material, a punch with single shear equal to thickness will[PI 2001]a)reduce the punch load to half the valueb)increase the punch load by half the valuec)maintain the same punch loadd)reduce the punch load to quarter loadCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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