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Determine the load required to punch a 20 mm diameter hole in 2 mm thick sheet. The properties of the material of the sheet are: Tensile strength – 580 MPa
Yield strength in tension – 410
MPa Shear strength – 350 MPa
Yield strength in shear – 250 MPa
Yield strength in tension – 410
MPa Shear strength – 350 MPa
Yield strength in shear – 250 MPa
The load in kN is
[PI 2004]
- a)31.40
- b)43.98
- c)64.40
- d)91.10
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Determine the load required to punch a 20 mm diameter hole in 2 mm thi...
Punching force = πDtτ
= π × 20 × 2 × 350 = 43.98 KN
= π × 20 × 2 × 350 = 43.98 KN
Most Upvoted Answer
Determine the load required to punch a 20 mm diameter hole in 2 mm thi...
The tensile strength of a material is the maximum amount of tensile (pulling) stress that it can withstand without breaking. In this case, we are given the tensile strength of the material, but we need to determine the load required to punch a hole in the sheet.
To determine the load required, we need to consider the shear strength of the material. Shear strength is the maximum amount of shear stress that a material can withstand without breaking.
In general, the load required to punch a hole in a sheet can be calculated using the following equation:
Load = Shear strength x Area of the hole
The area of the hole can be calculated using the formula for the area of a circle:
Area = π x (radius)^2
Given that the diameter of the hole is 20 mm, the radius would be half of that, or 10 mm (0.01 m).
Plugging in the values, we have:
Area = π x (0.01)^2 = 0.000314 m^2
Now we need to determine the shear strength of the material. Unfortunately, the given information does not include the shear strength, so we cannot calculate the load required to punch the hole without this information.
To determine the load required, we need to consider the shear strength of the material. Shear strength is the maximum amount of shear stress that a material can withstand without breaking.
In general, the load required to punch a hole in a sheet can be calculated using the following equation:
Load = Shear strength x Area of the hole
The area of the hole can be calculated using the formula for the area of a circle:
Area = π x (radius)^2
Given that the diameter of the hole is 20 mm, the radius would be half of that, or 10 mm (0.01 m).
Plugging in the values, we have:
Area = π x (0.01)^2 = 0.000314 m^2
Now we need to determine the shear strength of the material. Unfortunately, the given information does not include the shear strength, so we cannot calculate the load required to punch the hole without this information.
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Determine the load required to punch a 20 mm diameter hole in 2 mm thick sheet. The properties of the material of the sheet are: Tensile strength – 580 MPaYield strength in tension – 410MPa Shear strength – 350 MPaYield strength in shear – 250 MPaThe load in kN is[PI 2004]a)31.40b)43.98c)64.40d)91.10Correct answer is option 'B'. Can you explain this answer?
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