A pole has to be erected on the boundary of a circular park of diamete...

In right ΔAPB,
x
2 + (x + 7)
2 = 13
2⇒ x = 5 ∴ x + 7 = 12.
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A pole has to be erected on the boundary of a circular park of diamete...
Understanding the Problem
The problem involves a circular park with a diameter of 13 meters. The objective is to determine the distance of a pole erected on the boundary from one of two diametrically opposite gates, A and B, such that the difference in distances from the pole to these gates is 7 meters.
Key Information
- Diameter of the Park: 13 meters
- Radius of the Park: 6.5 meters (since radius = diameter / 2)
- Difference of Distances from Gates A and B: 7 meters
Assumptions and Setup
- Let the distances from the pole to gates A and B be represented as d_A and d_B, respectively.
- According to the problem, we have the equation: |d_A - d_B| = 7.
Using Geometric Properties
Since A and B are diametrically opposite, the maximum distance from any point on the boundary to either gate is equal to the diameter, which is 13 meters. Therefore, we can establish the following:
- If d_A is the distance from the pole to gate A, then d_B can be expressed as either:
- d_B = d_A - 7 (if d_A > d_B)
- d_B = d_A + 7 (if d_B > d_A)
However, d_A and d_B must also satisfy the condition that neither exceeds the maximum distance of 13 meters.
Calculating Possible Distances
1. Case 1: Assume d_A = d_B + 7
- d_A + d_B = 13 (from the property of circle)
- Solving gives d_B = 3 meters and d_A = 10 meters (not valid since 10 - 3 = 7)
2. Case 2: Assume d_B = d_A + 7
- d_A + d_B = 13
- Solving gives d_A = 3 meters and d_B = 10 meters (valid since 10 - 3 = 7)
Conclusion
From the calculations, the distance of the pole from gate A is confirmed to be 5 meters (which is not possible). Hence, the distance from gate A is:
- d_A = 5 meters (valid),
- d_B = 12 meters (7 meters difference is satisfied).
The correct answer is option 'C': 5 meters.
A pole has to be erected on the boundary of a circular park of diamete...

In right ΔAPB,
x
2 + (x + 7)
2 = 13
2⇒ x = 5 ∴ x + 7 = 12.