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Stems of bamboo, a tropical grass, can grow at the phenomenal rate of 0.3 m/d under optimal conditions. Given that the stems are composed almost entirely of cellulose fibres oriented in the direction of growth, calculate the number of sugar residues per second that must be added enzymatically to growing cellulose chains to account for the growth rate. Each D-glucose unit in the cellulose molecule is about 0.45 nm long.?
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Stems of bamboo, a tropical grass, can grow at the phenomenal rate of ...
Bamboo Growth Rate and Enzymatic Addition of Sugar Residues


Bamboo Growth Rate


  • Bamboo stems can grow at a rate of 0.3 m/d under optimal conditions.

  • Bamboo is a tropical grass.



Composition of Bamboo Stems


  • Bamboo stems are composed almost entirely of cellulose fibres.

  • The cellulose fibres are oriented in the direction of growth.



Enzymatic Addition of Sugar Residues


  • To account for the growth rate of bamboo stems, enzymatic addition of sugar residues to growing cellulose chains is necessary.

  • Each D-glucose unit in the cellulose molecule is about 0.45 nm long.

  • To calculate the number of sugar residues per second, we need to know the rate of growth in nm/s.

  • 0.3 m/d = 3.47 nm/s.

  • Assuming that the cellulose chains are growing linearly, we can calculate the number of D-glucose units added per second.

  • 3.47 nm/s / 0.45 nm per D-glucose unit = 7.71 D-glucose units added per second.



Explanation

Bamboo is a tropical grass that can grow at a phenomenal rate of 0.3 m/d under optimal conditions. Bamboo stems are composed almost entirely of cellulose fibres that are oriented in the direction of growth. To account for the growth rate of bamboo stems, enzymatic addition of sugar residues to growing cellulose chains is necessary. Each D-glucose unit in the cellulose molecule is about 0.45 nm long. Assuming that the cellulose chains are growing linearly, we can calculate the number of D-glucose units added per second, which is 7.71.
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Stems of bamboo, a tropical grass, can grow at the phenomenal rate of 0.3 m/d under optimal conditions. Given that the stems are composed almost entirely of cellulose fibres oriented in the direction of growth, calculate the number of sugar residues per second that must be added enzymatically to growing cellulose chains to account for the growth rate. Each D-glucose unit in the cellulose molecule is about 0.45 nm long.?
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Stems of bamboo, a tropical grass, can grow at the phenomenal rate of 0.3 m/d under optimal conditions. Given that the stems are composed almost entirely of cellulose fibres oriented in the direction of growth, calculate the number of sugar residues per second that must be added enzymatically to growing cellulose chains to account for the growth rate. Each D-glucose unit in the cellulose molecule is about 0.45 nm long.? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Stems of bamboo, a tropical grass, can grow at the phenomenal rate of 0.3 m/d under optimal conditions. Given that the stems are composed almost entirely of cellulose fibres oriented in the direction of growth, calculate the number of sugar residues per second that must be added enzymatically to growing cellulose chains to account for the growth rate. Each D-glucose unit in the cellulose molecule is about 0.45 nm long.? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Stems of bamboo, a tropical grass, can grow at the phenomenal rate of 0.3 m/d under optimal conditions. Given that the stems are composed almost entirely of cellulose fibres oriented in the direction of growth, calculate the number of sugar residues per second that must be added enzymatically to growing cellulose chains to account for the growth rate. Each D-glucose unit in the cellulose molecule is about 0.45 nm long.?.
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