Mechanical Engineering Exam  >  Mechanical Engineering Questions  >  The maximum reduction in cross-sectional area... Start Learning for Free
The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)
where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is
[ME 2018,Set-1]
  • a)
    0.865
  • b)
    0.826
  • c)
    0.777
  • d)
    0.632
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The maximum reduction in cross-sectional area per pass (R) of a cold w...
View all questions of this test
Most Upvoted Answer
The maximum reduction in cross-sectional area per pass (R) of a cold w...
It seems that the information provided is incomplete. The equation R = 1 is not sufficient to determine the maximum reduction in cross-sectional area per pass in a cold wire drawing process. Additional information or equations are needed to calculate the value of R.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer?
Question Description
The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer?.
Solutions for The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 – e–(n + 1)where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is[ME 2018,Set-1]a)0.865b)0.826c)0.777d)0.632Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev