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Let ABC be a right-angled isosceles triangle with hypotenuse BC. Let BQC be a semi-circle, away from A, with diameter BC. Let BPC be an arc of a circle centered at A and lying between BC and BQC. If AB has length 6 cm then the area, in sq cm, of the region enclosed by BPC and BQC is
(2017)
  • a)
    9π – 18
  • b)
    18π
  • c)
  • d)
    9
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let ABC be a right-angled isosceles triangle with hypotenuse BC. Let B...

Enclosed Area = Area of semi circle BQC with centre O – Area of Arc BPC with O
 ...(i)
Now, Area of triangle ABC + BPCO (Arc) = Area of Quarter circle (ABPC)

Area of BPCO = 9π –18
Put the value in equation (i)
Enclosed Area =  = 18 sq cm
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Most Upvoted Answer
Let ABC be a right-angled isosceles triangle with hypotenuse BC. Let B...

Enclosed Area = Area of semi circle BQC with centre O – Area of Arc BPC with O
 ...(i)
Now, Area of triangle ABC + BPCO (Arc) = Area of Quarter circle (ABPC)

Area of BPCO = 9π –18
Put the value in equation (i)
Enclosed Area =  = 18 sq cm
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Let ABC be a right-angled isosceles triangle with hypotenuse BC. Let BQC be a semi-circle, away from A, with diameter BC. Let BPC be an arc of a circle centered at A and lying between BC and BQC. If AB has length 6 cm then the area, in sq cm, of the region enclosed by BPC and BQC is(2017)a)9π – 18b)18πc)9πd)9Correct answer is option 'B'. Can you explain this answer?
Question Description
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