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A. When the reverse current in a particular zener diode increases from 20 mA to 30 mA, the zener voltage changes from 5.6 V to 5.65 V. What is the impedance of this device? B. What value of filter capacitor is required to produce a 1% ripple factor for a full-wave rectifier having a load resistance of 1.5 KΩ? Assume the rectifier produces a peak output of 18 V.?
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A. When the reverse current in a particular zener diode increases from...
A. Calculation of Impedance of Zener Diode
Given parameters:
Reverse current, IZ = 20 mA to 30 mA
Zener voltage, VZ = 5.6 V to 5.65 V

The change in current is ΔI = 30 mA – 20 mA = 10 mA
The change in voltage is ΔV = 5.65 V – 5.6 V = 0.05 V

The dynamic impedance of the zener diode can be calculated as:
Z = ΔV / ΔI = 0.05 V / 10 mA = 5 Ω

Therefore, the impedance of this zener diode is 5 Ω.

B. Calculation of Filter Capacitor for Full-Wave Rectifier
Given parameters:
Load resistance, RL = 1.5 KΩ
Peak output voltage, Vp = 18 V
Ripple factor, γ = 1%

The ripple factor is given by the formula:
γ = Vrms / Vdc
where Vrms is the root mean square value of the ripple voltage and Vdc is the average DC voltage.

The average DC voltage can be calculated as:
Vdc = Vp / π = 18 V / π ≈ 5.73 V

The ripple voltage can be calculated as:
Vr = Vdc * γ = 5.73 V * 0.01 = 0.0573 V

The root mean square value of the ripple voltage can be calculated as:
Vrms = Vr / √3 ≈ 0.033 V

The capacitance required to produce this ripple factor can be calculated using the formula:
C = Iload / (2 * π * f * Vr)
where Iload is the load current, f is the frequency, and Vr is the ripple voltage.

For a full-wave rectifier, the load current is given by:
Iload = Vp / RL = 18 V / 1.5 KΩ ≈ 12 mA

Assuming a frequency of 50 Hz, the capacitance required can be calculated as:
C = 12 mA / (2 * π * 50 Hz * 0.033 V) ≈ 114 µF

Therefore, a filter capacitor of approximately 114 µF is required to produce a 1% ripple factor for a full-wave rectifier with a load resistance of 1.5 KΩ.
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A. When the reverse current in a particular zener diode increases from 20 mA to 30 mA, the zener voltage changes from 5.6 V to 5.65 V. What is the impedance of this device? B. What value of filter capacitor is required to produce a 1% ripple factor for a full-wave rectifier having a load resistance of 1.5 KΩ? Assume the rectifier produces a peak output of 18 V.?
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A. When the reverse current in a particular zener diode increases from 20 mA to 30 mA, the zener voltage changes from 5.6 V to 5.65 V. What is the impedance of this device? B. What value of filter capacitor is required to produce a 1% ripple factor for a full-wave rectifier having a load resistance of 1.5 KΩ? Assume the rectifier produces a peak output of 18 V.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A. When the reverse current in a particular zener diode increases from 20 mA to 30 mA, the zener voltage changes from 5.6 V to 5.65 V. What is the impedance of this device? B. What value of filter capacitor is required to produce a 1% ripple factor for a full-wave rectifier having a load resistance of 1.5 KΩ? Assume the rectifier produces a peak output of 18 V.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A. When the reverse current in a particular zener diode increases from 20 mA to 30 mA, the zener voltage changes from 5.6 V to 5.65 V. What is the impedance of this device? B. What value of filter capacitor is required to produce a 1% ripple factor for a full-wave rectifier having a load resistance of 1.5 KΩ? Assume the rectifier produces a peak output of 18 V.?.
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