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In standard penetration test, the splitspoon sampler is penetrated into the soil stratum by giving blows from a drop weight whose weight(in kg) and free fall (in cm) are, respectively
  • a)
    30 and 60
  • b)
    60 and 30
  • c)
    65 and 75
  • d)
    75 and 65
Correct answer is option 'C'. Can you explain this answer?
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In standard penetration test, the splitspoon sampler is penetrated int...
Splitspoon Sampler in Standard Penetration Test

The Standard Penetration Test (SPT) is a widely used in-situ test for soil investigation. It is a simple and quick test that provides information about the soil resistance to penetration. The SPT uses a split-spoon sampler that is driven into the soil by a drop weight.

Components of SPT

The SPT consists of the following components:

- Split-spoon sampler: It is a cylindrical tube that is split into two halves longitudinally. It is inserted into the soil by the blows of a drop weight.
- Drop weight: It is a hammer that is lifted to a certain height and allowed to fall on the split-spoon sampler.
- Drive rod: It is a steel pipe that is used to drive the split-spoon sampler into the soil.
- Tripod: It is a three-legged stand that supports the drop weight during the test.
- Measuring tape: It is used to measure the depth of penetration of the split-spoon sampler.

Parameters of Drop Weight

The weight and free fall of the drop weight are important parameters in the SPT. The weight of the drop weight is usually 65 kg or 75 kg. The free fall of the drop weight is usually 75 cm or 60 cm. The product of the weight and free fall is called the energy delivered by the drop weight. The higher the energy delivered, the deeper the split-spoon sampler can penetrate into the soil.

Answer Explanation

In the given question, the weight and free fall of the drop weight are not provided directly. However, we can calculate them using the energy delivered by the drop weight. The energy delivered is equal to the product of the weight and free fall. We can set up the following equations:

- 30W = 60H (Option A)
- 60W = 30H (Option B)
- 65W = 75H (Option C)
- 75W = 65H (Option D)

where W is the weight of the drop weight in kg and H is the free fall of the drop weight in cm.

Solving these equations, we get:

- W = 2H (Option A)
- W = 0.5H (Option B)
- W = 1.154H (Option C)
- W = 0.867H (Option D)

We can see that only Option C satisfies the condition that the weight and free fall are both integers. Therefore, the correct answer is Option C, which corresponds to a drop weight of 65 kg and a free fall of 75 cm.
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In standard penetration test, the splitspoon sampler is penetrated into the soil stratum by giving blows from a drop weight whose weight(in kg) and free fall (in cm) are, respectivelya)30 and 60b)60 and 30c)65 and 75d)75 and 65Correct answer is option 'C'. Can you explain this answer?
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In standard penetration test, the splitspoon sampler is penetrated into the soil stratum by giving blows from a drop weight whose weight(in kg) and free fall (in cm) are, respectivelya)30 and 60b)60 and 30c)65 and 75d)75 and 65Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about In standard penetration test, the splitspoon sampler is penetrated into the soil stratum by giving blows from a drop weight whose weight(in kg) and free fall (in cm) are, respectivelya)30 and 60b)60 and 30c)65 and 75d)75 and 65Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In standard penetration test, the splitspoon sampler is penetrated into the soil stratum by giving blows from a drop weight whose weight(in kg) and free fall (in cm) are, respectivelya)30 and 60b)60 and 30c)65 and 75d)75 and 65Correct answer is option 'C'. Can you explain this answer?.
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