The water table in the deposit of sand 8.0 meter thick is at a depth o...
Given information:
- Thickness of sand deposit (h) = 8.0 m
- Depth of water table (d) = 3.0 m
- Bulk density of sand (γ) = 19.620 kN/m3
To find: Effective pressure at a depth of 8 m below the surface.
Solution:
1. Calculate the total vertical stress at a depth of 8 m:
Total vertical stress (σv) = γ × h
σv = 19.620 kN/m3 × 8.0 m
σv = 156.96 kN/m2
2. Calculate the pore water pressure at the depth of the water table:
Pore water pressure (u) = γw × d
Assuming specific gravity of water to be 1,
u = 9.81 kN/m3 × 3.0 m
u = 29.43 kN/m2
3. Calculate the effective stress at the depth of the water table:
Effective stress (σ') = σv - u
σ' = 156.96 kN/m2 - 29.43 kN/m2
σ' = 127.53 kN/m2
4. Calculate the vertical effective stress at a depth of 8 m:
Vertical effective stress (σ'vertical) = σ' × (h - d) / h
σ'vertical = 127.53 kN/m2 × (8.0 m - 3.0 m) / 8.0 m
σ'vertical = 102.03 kN/m2
5. Calculate the horizontal effective stress at a depth of 8 m:
Assuming the soil to be isotropic (i.e., equal in all directions), the horizontal effective stress (σ'horizontal) is equal to one-third of the vertical effective stress.
σ'horizontal = 1/3 × σ'vertical
σ'horizontal = 1/3 × 102.03 kN/m2
σ'horizontal = 34.01 kN/m2
6. Calculate the effective pressure at a depth of 8 m:
Effective pressure (P') = σ'horizontal + σ'vertical
P' = 34.01 kN/m2 + 102.03 kN/m2
P' = 136.04 kN/m2
Therefore, the effective pressure at a depth of 8 m below the surface is 136.04 kN/m2 (approximately 107.91 kN/m2, rounded off to two decimal places).
Answer: A) 107.91 kN/m2
The water table in the deposit of sand 8.0 meter thick is at a depth o...
107.91 kn/m2