Oxidation state of Fe in Fe3O4 ?

Question

Answer

fractional oxiadation state of 8/3= 2.667yes you r right!yes one of the fe atom shows +2 oxidation no. while the other two show +3 oxidation no. This takes place due -2 oxidation state of oxygen

Answer

8/3

Answer

8/3

Answer

fe here is having two o.s one +2 and other being +3feo  &fe2O3

Answer

8/3

Answer

2 /3

Answer

8/3

Answer

fractional  oxidation state is 2.667

Answer

8/3

Answer

Feo=0then,Fe×1+(-2)=0then,Fe=+2&&FeO3=0then,Fe+(-2)×3=0then,Fe=+6so,the oxidation state of Fe is +2 & +6

Answer

8/3

Answer

The Oxidation State of Fe in Fe3O4

Fe3O4, also known as magnetite, is an iron oxide compound consisting of three iron (Fe) atoms and four oxygen (O) atoms. The oxidation state of an element refers to the charge it carries when it forms a compound or ion. In the case of Fe3O4, the oxidation state of iron can be determined by considering the overall charge of the compound and the known oxidation states of oxygen.

1. Oxidation States of Oxygen:
Oxygen generally has an oxidation state of -2 in most compounds. Since there are four oxygen atoms in Fe3O4, the total negative charge contributed by oxygen is -8.

2. Overall Charge of Fe3O4:
To determine the oxidation state of iron in Fe3O4, we need to consider the overall charge of the compound. Fe3O4 is a neutral compound, which means the sum of the charges must be zero.

3. Calculating the Oxidation State of Iron:
Since the overall charge of Fe3O4 is zero, the sum of the oxidation states of iron must balance the -8 charge contributed by oxygen.

Let's assume the oxidation state of iron in Fe3O4 is x.

- Multiply the oxidation state of iron by the number of iron atoms (3) to get the total charge contributed by iron: 3x.
- Add the total charge contributed by iron (3x) to the total negative charge contributed by oxygen (-8) to get the overall charge of the compound.
- Set the overall charge equal to zero: 3x + (-8) = 0.
- Simplify the equation: 3x = 8.
- Solve for x: x = 8/3.

So, the oxidation state of iron (Fe) in Fe3O4 is +8/3, or we can say it is +8/3 per iron atom.

Conclusively, the oxidation state of iron in Fe3O4 is +8/3.

Similar Class 11 Doubts

For the four successive transition elements (Cr, Mn, Fe and Co), the stability of + 2 oxidation state will be there in which of the following order? (At. nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

Oxidation state of oxygen in h2o2?

What is the oxidation state of So2- ?

What is oxidation state of S in Na²So2O3?

oxidation number of iron in Na2[Fe(CN)5(NO+)]

Top Courses for Class 11View all

Chemistry Class 11

CUET Mock Test Series

English Class 11

Chemistry Practice Tests: CUET Preparation

CUET Mock Test: Humanities Subjects 2025

Top Courses for Class 11

Top Courses for Class 11

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams