what is the oxidation state of haemoglobin present in iron

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what is the oxidation state of haemoglobin present in iron

oxyhaemoglobin

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The familiar brown ring test for nitrates depends on the ability of Fe2+ to reduce nitrates to nitric oxide, which reacts with Fe2+ to form a brown coloured complex [Fe(H2O)5NO+]SO4. What is the oxidation state of iron in the complex. (Only write the number 1, 2, 3, ......) Correct answer is '1433'. Can you explain this answer?

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Haemoglobin contains 0.334% of iron by weight. If molecular weight of haemoglobin is approximately 67200, then the number of iron atoms (At.wt. of Fe is 56) present in one molecule of haemoglobin are

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This section contains 5 questions. Each question, when worked out will result in one integer from 0 to 9 (both inclusiv e).Sulphide ion react with Na2[Fe(NO)(CN)5] to form a purple coloured compound Na4[Fe(CN)5NOS]. In this reaction the change in oxidation state of iron is? Correct answer is '0'. Can you explain this answer?

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Each mole of Haemoglobin contains four moles of iron .if the percentage of iron in Haemoglobin is 0.35% by mass .the molar mass of Haemoglobin is 1)6.410⁴gmol^-1. 2) 5.610⁴ gmol^-1. 3)6.410^5 gmol^-1 4)5.610^5 gmol^-1

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A blue colour complex is obtained in the analysis of Fe+3 having formula Fe4[Fe(CN)6]3Let a = oxidation number of iron in the coordination sphere, b = no. of secondary valencies of central iron ion. C = Effective atomic number of iron in the coordination sphere.Then find the value of (c + a − 2 b). Correct answer is '26'. Can you explain this answer?

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