A shopkeeper bought 200 pens and 300 pencils for a total of Rs.6000. h...
Problem: A shopkeeper bought 200 pens and 300 pencils for a total of Rs.6000. He sold 40% pens at 20% profit and the rest pens at x% profit. He sold 60% pencils at 40% profit and the rest pencils at y% profit. The shopkeeper got Rs.10400 by selling all the articles. If he had got 35% profit on pencils, then find x:y?
Solution:
Let the cost price of one pen be 'a' and the cost price of one pencil be 'b'. Therefore,
Total cost of 200 pens = 200a
Total cost of 300 pencils = 300b
Total cost of 200 pens and 300 pencils = 200a + 300b = Rs.6000
Thus, a+3/2b=30 or 2a+3b=6000/1000=6
Let the selling price of 40% of pens be SP1 and the selling price of the rest of the pens be SP2. Also, let the selling price of 60% of pencils be SP3 and the selling price of the rest of the pencils be SP4.
Given that the shopkeeper sold 40% of pens at 20% profit, we have:
SP1 = 1.2 × 0.4 × 200a + 0.4 × 200a = 96a + 80a = 176a
The remaining 60% of pens were sold at x% profit, hence:
SP2 = 1.x × 0.6 × 200a + 0.6 × 200a = 1.2xa
Similarly, the shopkeeper sold 60% of pencils at 40% profit, thus:
SP3 = 1.4 × 0.6 × 300b = 252b
The remaining 40% of pencils were sold at y% profit, hence:
SP4 = 1.y × 0.4 × 300b = 1.2yb
The total selling price of all the articles = SP1 + SP2 + SP3 + SP4 = Rs.10400
Substituting the values of SP1, SP2, SP3, and SP4, we get:
176a + 1.2xa + 252b + 1.2yb = 10400
Simplifying this equation, we get:
176a + 1.2xa + 252b + 1.2yb = 10400
=> 264a + 360b = 10400
=> 33a + 45b = 1300 ---(1)
Also, given that the shopkeeper got 35% profit on pencils, we have:
SP3 + SP4 = 1.35 × 300b = 405b
Substituting the values of SP3 and SP4, we get:
252b + 1.2yb = 405b
=> y = 37.5%
Therefore, x:y = 20:37.5 = 8:15
Hence, the required ratio is 8:15.
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