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An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be
[1989]
- a)no normal stress
- b)also the maximum normal stress
- c)the minimum normal stress
- d)both normal stress and shear stress
Correct answer is option 'C'. Can you explain this answer?
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An elastic body is subjected to a tensile stress X in a particular dir...
Explanation:
When an elastic body is subjected to tensile and compressive stresses in perpendicular directions, the stresses can be resolved into normal and shear stresses. The direction of maximum shear stress is at an angle of 45 degrees with the direction of the tensile and compressive stresses. On this plane, the normal stresses are equal in magnitude and opposite in sign.
In this case, X and Y are unequal in magnitude, so the plane of maximum shear stress will not coincide with the plane of maximum normal stress. Therefore, there will be no normal stress on the plane of maximum shear stress.
However, there will be a minimum normal stress on the plane of maximum shear stress. This is because the normal stresses are equal in magnitude and opposite in sign on this plane. Therefore, the magnitude of the normal stress on this plane will be equal to the difference between the magnitudes of the tensile and compressive stresses. As X and Y are unequal in magnitude, the difference between them will result in a non-zero minimum normal stress on the plane of maximum shear stress.
Hence, option C is the correct answer.
When an elastic body is subjected to tensile and compressive stresses in perpendicular directions, the stresses can be resolved into normal and shear stresses. The direction of maximum shear stress is at an angle of 45 degrees with the direction of the tensile and compressive stresses. On this plane, the normal stresses are equal in magnitude and opposite in sign.
In this case, X and Y are unequal in magnitude, so the plane of maximum shear stress will not coincide with the plane of maximum normal stress. Therefore, there will be no normal stress on the plane of maximum shear stress.
However, there will be a minimum normal stress on the plane of maximum shear stress. This is because the normal stresses are equal in magnitude and opposite in sign on this plane. Therefore, the magnitude of the normal stress on this plane will be equal to the difference between the magnitudes of the tensile and compressive stresses. As X and Y are unequal in magnitude, the difference between them will result in a non-zero minimum normal stress on the plane of maximum shear stress.
Hence, option C is the correct answer.
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An elastic body is subjected to a tensile stress X in a particular dir...
Assuming more tensile stress, hence the centre of the circle lies on positive side of X axis. So, the plane CP has maximum shear stress which has non zero normal stress.
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An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be[1989]a)no normal stressb)also the maximum normal stressc)the minimum normal stressd)both normal stress and shear stressCorrect answer is option 'C'. Can you explain this answer?
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An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be[1989]a)no normal stressb)also the maximum normal stressc)the minimum normal stressd)both normal stress and shear stressCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be[1989]a)no normal stressb)also the maximum normal stressc)the minimum normal stressd)both normal stress and shear stressCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be[1989]a)no normal stressb)also the maximum normal stressc)the minimum normal stressd)both normal stress and shear stressCorrect answer is option 'C'. Can you explain this answer?.
An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be[1989]a)no normal stressb)also the maximum normal stressc)the minimum normal stressd)both normal stress and shear stressCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be[1989]a)no normal stressb)also the maximum normal stressc)the minimum normal stressd)both normal stress and shear stressCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be[1989]a)no normal stressb)also the maximum normal stressc)the minimum normal stressd)both normal stress and shear stressCorrect answer is option 'C'. Can you explain this answer?.
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