JEE Exam > JEE Questions > A stationary ball weighing 0.25kg acquires a ...
Start Learning for Free
A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball is
- a)1.5 Ns
- b)0.5 Ns
- c)2.5 Ns
- d)2.0 Ns
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit b...
Initial momentum of the ball,
Pi = 0
Final momentum of the ball,
Pf = mv
⇒ 0.25×10 = 2.5 kg m/s
Impulse imparted on the ball,
I = Pf − Pi
⇒ I = 2.5 − 0 = 2.5 N s
Pi = 0
Final momentum of the ball,
Pf = mv
⇒ 0.25×10 = 2.5 kg m/s
Impulse imparted on the ball,
I = Pf − Pi
⇒ I = 2.5 − 0 = 2.5 N s
Most Upvoted Answer
A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit b...
To solve this problem, we can use the principle of impulse-momentum. The impulse imparted to an object is equal to the change in momentum of the object.
Momentum is defined as the product of an object's mass and its velocity. In this case, the ball has a mass of 0.25 kg and acquires a speed of 10 m/s when hit by the hockey stick. Therefore, the initial momentum of the ball is zero (since it is stationary) and the final momentum is given by:
Final momentum = mass × final velocity
= 0.25 kg × 10 m/s
= 2.5 kg·m/s
The change in momentum is the difference between the final momentum and the initial momentum:
Change in momentum = Final momentum - Initial momentum
= 2.5 kg·m/s - 0 kg·m/s
= 2.5 kg·m/s
According to the principle of impulse-momentum, the impulse imparted to the ball is equal to the change in momentum. Therefore, the impulse imparted to the ball is 2.5 kg·m/s.
Hence, the correct answer is option C, 2.5 Ns.
Momentum is defined as the product of an object's mass and its velocity. In this case, the ball has a mass of 0.25 kg and acquires a speed of 10 m/s when hit by the hockey stick. Therefore, the initial momentum of the ball is zero (since it is stationary) and the final momentum is given by:
Final momentum = mass × final velocity
= 0.25 kg × 10 m/s
= 2.5 kg·m/s
The change in momentum is the difference between the final momentum and the initial momentum:
Change in momentum = Final momentum - Initial momentum
= 2.5 kg·m/s - 0 kg·m/s
= 2.5 kg·m/s
According to the principle of impulse-momentum, the impulse imparted to the ball is equal to the change in momentum. Therefore, the impulse imparted to the ball is 2.5 kg·m/s.
Hence, the correct answer is option C, 2.5 Ns.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
Question Description
A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer?.
A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A stationary ball weighing 0.25kg acquires a speed of 10m/s when hit by a hockey stick. The impulse imparted to the ball isa)1.5 Nsb)0.5 Nsc)2.5 Nsd)2.0 NsCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup