How many two-digit whole numbers yield a remainder of 1 when divided b...
To find the two-digit whole numbers that satisfy the given conditions, we need to determine the numbers that leave a remainder of 1 when divided by both 10 and 6.
We can start by considering the multiples of 10. The multiples of 10 are numbers that end with a zero, such as 10, 20, 30, and so on. However, none of these numbers leaves a remainder of 1 when divided by 6. Therefore, we can conclude that none of the multiples of 10 are suitable solutions.
Next, let's consider the numbers that leave a remainder of 1 when divided by 6. Such numbers can be represented as 6n + 1, where n is an integer. To find the two-digit numbers that satisfy this condition, we can substitute values of n and check if the resulting number is within the range of two-digit numbers (10 to 99).
If we substitute n = 0, we get 6(0) + 1 = 1, which is not a two-digit number. Similarly, if we substitute n = 1, we get 6(1) + 1 = 7, which is also not a two-digit number. However, when we substitute n = 2, we get 6(2) + 1 = 13, which is a two-digit number.
Therefore, the number 13 satisfies the given conditions.
To check if there are any other two-digit numbers that satisfy the conditions, we can continue substituting larger values of n. If we substitute n = 3, we get 6(3) + 1 = 19, which is also a two-digit number. Finally, if we substitute n = 4, we get 6(4) + 1 = 25, which is not a two-digit number.
Thus, we have found two two-digit numbers (13 and 19) that satisfy the given conditions. Therefore, the correct answer is option D: Three.
How many two-digit whole numbers yield a remainder of 1 when divided b...
Three