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a wire is in the shape of a rectangle. it's length is 40cm and breadth is 22cm. if the same wire is ribend in the shape of a square. what will be the measure of each side. also find which shape encloses more area??? PLEASE ANSWER THIS QUESTION I NEED IT FOR TOMORROW
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a wire is in the shape of a rectangle. it's length is 40cm and breadth...
Length of wire = 40 cm

Breadth of wire = 22 cm

=> Perimeter of Wire = 2 ( l + b )

=> Perimeter = 2 ( 40 + 22 )

=> Perimeter = 2 ( 62 ) = 124 cm

Hence perimeter of wire in the shape of rectangle is 124 cm.

Now it is in the form of square. So let us assume the side to be 'a'.

=> Perimeter of Square = Perimeter of Rectangle

=> 4 a = 124

=> a = 124 / 4 = 31

Hence one side of a square is 31 cm.

Area of Rectangle = l x b

=> Area of Rectangle = 40 x 22 = 880 cm�

Area of Square = a^2

=> Area of Square = 31 x 31 = 961 cm^2

So the area covered by square is more than that of area covered by rectangle.

Area Difference = 961 - 880 = 81 cm^2

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a wire is in the shape of a rectangle. it's length is 40cm and breadth...
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a wire is in the shape of a rectangle. it's length is 40cm and breadth is 22cm. if the same wire is ribend in the shape of a square. what will be the measure of each side. also find which shape encloses more area??? PLEASE ANSWER THIS QUESTION I NEED IT FOR TOMORROW
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