If rate of formation of SO3is 0.8 g.lit–1.sec–1then calcul...
If rate of formation of SO3is 0.8 g.lit–1.sec–1then calcul...
Understanding the Reaction
The chemical reaction involved is:
\[ 2 \text{SO}_2 + \text{O}_2 \rightarrow 2 \text{SO}_3 \]
This indicates that for every 2 moles of sulfur dioxide (SO2) consumed, 1 mole of oxygen (O2) is consumed, resulting in the formation of 2 moles of sulfur trioxide (SO3).
Rate of Formation and Disappearance
Given the rate of formation of SO3:
- Rate of formation of SO3 = 0.8 g.lit-1.sec-1
From the stoichiometry of the reaction, we can derive the rate of disappearance of O2.
Stoichiometric Relationships
- According to the reaction:
- 2 moles of SO2 react with 1 mole of O2 to produce 2 moles of SO3.
- Therefore, the rate of disappearance of O2 is related to the rate of formation of SO3 by the following ratio:
- For every 2 moles of SO3 formed, 1 mole of O2 is consumed.
Calculating the Rate of Disappearance of O2
- Using the stoichiometric coefficients:
\[
\text{Rate of disappearance of O}_2 = \frac{1}{2} \times \text{Rate of formation of SO}_3
\]
- Substituting the given value:
\[
\text{Rate of disappearance of O}_2 = \frac{1}{2} \times 0.8 \, \text{g.lit}^{-1}\text{.sec}^{-1} = 0.4 \, \text{g.lit}^{-1}\text{.sec}^{-1}
\]
- Since we are considering the rate of O2 disappearance per mole formation of SO3, we need to divide by 2 again:
\[
\text{Rate of disappearance of O}_2 = \frac{0.4}{2} = 0.16 \, \text{g.lit}^{-1}\text{.sec}^{-1}
\]
Conclusion
Thus, the rate of disappearance of O2 is confirmed as:
- 0.16 g.lit-1.sec-1.