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A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earth's magnetic field at these two places is x : 9√3, find x :-
Correct answer is '16'. Can you explain this answer?
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A bar magnet is freely suspended in such a way that, when it oscillate...
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The dip angle, also known as the magnetic inclination, is the angle between the horizontal plane and the total intensity vector of the Earth's magnetic field. It is denoted by the symbol δ.
In this case, the dip angle is given as 30°.
To find the magnetic field strength, we can use the formula:
B = H / cos(δ)
where B is the magnetic field strength and H is the horizontal component of the Earth's magnetic field.
Since the magnet is freely suspended and oscillates in the horizontal plane, it aligns itself with the horizontal component of the Earth's magnetic field. Therefore, the magnetic field strength is equal to the horizontal component.
Let's assume the horizontal component of the Earth's magnetic field is denoted by H0.
Now, we can rearrange the formula to solve for H0:
H0 = B * cos(δ)
We are given that the bar magnet makes 20 oscillations per minute at the place where the dip angle is 30°. This means that the time period of each oscillation is 1/20 minutes.
The time period (T) of an oscillation can be related to the magnetic field strength (B) and the magnetic moment (m) of the bar magnet using the formula:
T = 2π * √(I / (B * m))
where I is the moment of inertia of the bar magnet.
In this case, we are not given the moment of inertia or the magnetic moment of the bar magnet, so we cannot directly calculate the magnetic field strength or the horizontal component of the Earth's magnetic field.
In this case, the dip angle is given as 30°.
To find the magnetic field strength, we can use the formula:
B = H / cos(δ)
where B is the magnetic field strength and H is the horizontal component of the Earth's magnetic field.
Since the magnet is freely suspended and oscillates in the horizontal plane, it aligns itself with the horizontal component of the Earth's magnetic field. Therefore, the magnetic field strength is equal to the horizontal component.
Let's assume the horizontal component of the Earth's magnetic field is denoted by H0.
Now, we can rearrange the formula to solve for H0:
H0 = B * cos(δ)
We are given that the bar magnet makes 20 oscillations per minute at the place where the dip angle is 30°. This means that the time period of each oscillation is 1/20 minutes.
The time period (T) of an oscillation can be related to the magnetic field strength (B) and the magnetic moment (m) of the bar magnet using the formula:
T = 2π * √(I / (B * m))
where I is the moment of inertia of the bar magnet.
In this case, we are not given the moment of inertia or the magnetic moment of the bar magnet, so we cannot directly calculate the magnetic field strength or the horizontal component of the Earth's magnetic field.
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A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer?
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A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer?.
A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer?.
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A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer?, a detailed solution for A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer? has been provided alongside types of A bar magnet is freely suspended in such a way that, when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place, where dip angle is 30° and 15 oscillations per minute at a place, where dip angle is 60°. Ratio of total earths magnetic field at these two places is x : 9√3,find x :-Correct answer is '16'. Can you explain this answer? theory, EduRev gives you an
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