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Two similar bar magnets of the same mass and dimensions freely suspended by threads in a horizontal plane are found to make 12 oscillations and 15 oscillations per minute. Then their magnetic moments are in the ratio of
  • a)
    4:5
  • b)
    5:4
  • c)
    144:225
  • d)
    225:144
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two similar bar magnets of the same mass and dimensions freely suspend...
Concept:
The time period of oscillation of a bar magnet in a magnetic field is given by:
\[T = 2\pi\sqrt{\frac{I}{M B}}\]
where,
T = time period of oscillation,
I = moment of inertia of the magnet,
M = magnetic moment of the magnet,
B = magnetic field strength.

Given:
Number of oscillations for first magnet = 12 per minute = 12/60 = 0.2 Hz
Number of oscillations for second magnet = 15 per minute = 15/60 = 0.25 Hz

Calculation:
Let the magnetic moments of the two magnets be \(M_1\) and \(M_2\).
For the first magnet:
\[T_1 = \frac{1}{0.2} = 5s\]
\[M_1 = \frac{4\pi^2 I}{T_1^2 B}\]
For the second magnet:
\[T_2 = \frac{1}{0.25} = 4s\]
\[M_2 = \frac{4\pi^2 I}{T_2^2 B}\]
Now, the ratio of magnetic moments:
\[\frac{M_1}{M_2} = \frac{T_2^2}{T_1^2} = \frac{16}{25} = \frac{144}{225}\]
Therefore, the magnetic moments are in the ratio 144:225, which corresponds to option (c).
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Two similar bar magnets of the same mass and dimensions freely suspended by threads in a horizontal plane are found to make 12 oscillations and 15 oscillations per minute. Then their magnetic moments are in the ratio ofa)4:5b)5:4c)144:225d)225:144Correct answer is option 'C'. Can you explain this answer?
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