A very large number of balls are thrown vertically upwards in quick su...
For max. height h = 5 m
initial velocity
So time taken for max-height
So balls are thrown at interval of 1 sec.
So per min. thrown balls are = 60
A very large number of balls are thrown vertically upwards in quick su...
Given:
- The maximum height of each ball is 5m.
- The next ball is thrown when the previous one is at maximum height.
To find:
- The number of balls thrown per minute.
Solution:
Let's assume that it takes t seconds for a ball to reach its maximum height of 5m.
- The time taken by the first ball to reach the maximum height is t seconds.
- The second ball is thrown when the first ball is at the maximum height, so it will take t seconds to reach the maximum height.
- Similarly, the third ball will be thrown when the second ball is at the maximum height, so it will take t seconds to reach the maximum height.
- This pattern will continue for all the balls.
Therefore, the time taken for n balls to reach their maximum height will be n*t seconds.
Now, we need to find the number of balls thrown per minute.
- 1 minute = 60 seconds.
- So, the number of balls thrown in 1 minute will be the number of balls that can reach their maximum height in 60 seconds.
Let's assume that in 60 seconds, m balls can reach their maximum height.
- Then the time taken for m balls to reach their maximum height will be m*t seconds.
- We know that n balls take n*t seconds to reach their maximum height.
- So, we can write n*t = m*t
- This implies that n = m
Hence, the number of balls thrown per minute will be equal to the number of balls that can reach their maximum height in 60 seconds.
- As we have seen above, this number is n.
- Therefore, the number of balls thrown per minute is n.
- Since we know that each ball takes t seconds to reach its maximum height, we can calculate the value of n using the formula:
n = (60/t)
- Therefore, the number of balls thrown per minute is 60/t.
Answer:
- The correct answer is 60.