Steam is supplied to a turbine at pressure 11 bar with a dryness fract...
Given data:
Inlet pressure of steam (P1) = 11 bar
Dryness fraction of steam (d) = ?
Outlet pressure of steam (P2) = 0.07 bar
(a) Heat Supplied:
The heat supplied to the turbine can be calculated by using the equation:
h1 = hf + d * (hfg)
where,
hf = Enthalpy of saturated liquid at inlet pressure
hfg = Enthalpy of vaporization at inlet pressure
From steam tables, at 11 bar:
hf = 727.64 kJ/kg
hfg = 1936.8 kJ/kg
Therefore, h1 = 727.64 + d * 1936.8 kJ/kg
(b) Total Change in Entropy:
As the process is isentropic, the total change in entropy (ΔS) can be calculated by using the equation:
ΔS = s2 - s1
where,
s1 = Entropy of steam at inlet pressure
s2 = Entropy of steam at outlet pressure
From steam tables, at 11 bar:
s1 = 6.333 kJ/kg.K
From steam tables, at 0.07 bar:
s2 = 7.417 kJ/kg.K
Therefore, ΔS = 7.417 - 6.333 kJ/kg.K
(c) Heat Rejected:
The heat rejected by the turbine can be calculated by using the equation:
Qr = h1 - h2
where,
h2 = Enthalpy of steam at outlet pressure
From steam tables, at 0.07 bar:
h2 = 2507.2 kJ/kg
Therefore, Qr = h1 - h2 kJ/kg
(d) Thermal Efficiency:
The thermal efficiency (η) of the turbine can be calculated by using the equation:
η = (Wt / Qs) * 100%
where,
Wt = Work done by the turbine
Qs = Heat supplied to the turbine
The work done by the turbine can be calculated by using the equation:
Wt = h1 - h2
From the above calculations,
Qs = h1 - hf kJ/kg
Wt = h1 - h2 kJ/kg
Therefore, η = [(h1 - h2) / (h1 - hf)] * 100%
Note: The above calculations assume ideal conditions and do not take into account any losses that may occur in the turbine.
Steam is supplied to a turbine at pressure 11 bar with a dryness fract...
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