JEE Exam  >  JEE Questions  >  A solution of glucose in water is labelled as... Start Learning for Free
A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.?
Most Upvoted Answer
A solution of glucose in water is labelled as 10% (w/w) the density of...
1. Molality:
Molality is defined as the number of moles of solute per kilogram of solvent. To calculate molality, we need to determine the number of moles of glucose and the mass of water.

Given:
Percentage concentration of glucose = 10% (w/w)
Density of the solution = 1.20 g/mL

Since the percentage concentration is given in terms of weight/weight (w/w), it means that for every 100 grams of the solution, 10 grams is glucose and 90 grams is water.

Let's assume we have 100 g of the solution. Therefore, the mass of glucose (solute) is 10 g and the mass of water (solvent) is 90 g.

Next, we need to convert the mass of glucose to moles. To do this, we divide the mass of glucose by its molar mass. The molar mass of glucose (C6H12O6) is 180 g/mol.

Number of moles of glucose = 10 g / 180 g/mol = 0.0556 mol

Now, we calculate the molality using the formula:
Molality (m) = moles of solute / mass of solvent (in kg)

Mass of water (solvent) = 90 g = 0.09 kg

Molality = 0.0556 mol / 0.09 kg = 0.617 mol/kg

Therefore, the molality of the solution is 0.617 mol/kg.

2. Molarity:
Molarity is defined as the number of moles of solute per liter of solution. To calculate molarity, we need to determine the number of moles of glucose and the volume of the solution.

Given:
Percentage concentration of glucose = 10% (w/w)
Density of the solution = 1.20 g/mL

Since the percentage concentration is given in terms of weight/weight (w/w), it means that for every 100 grams of the solution, 10 grams is glucose and 90 grams is water.

Let's assume we have 100 mL of the solution. Therefore, the mass of the solution is 120 g (100 mL x 1.20 g/mL).

The mass of glucose (solute) is 10 g. To convert this to moles, we divide the mass by the molar mass of glucose (180 g/mol).

Number of moles of glucose = 10 g / 180 g/mol = 0.0556 mol

Now, we calculate the molarity using the formula:
Molarity (M) = moles of solute / volume of solution (in L)

Volume of solution = 100 mL = 0.1 L

Molarity = 0.0556 mol / 0.1 L = 0.556 M

Therefore, the molarity of the solution is 0.556 M.

3. Mole Fraction:
Mole fraction is defined as the ratio of moles of a component to the total moles of all components in the solution.

To calculate the mole fraction of each component (glucose and water), we first need to determine the moles of each component.

Given:
Percentage concentration of glucose = 10% (w/w)
Density of the solution = 1.20 g/mL

For every
Explore Courses for JEE exam
A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.?
Question Description
A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.?.
Solutions for A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.? defined & explained in the simplest way possible. Besides giving the explanation of A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.?, a detailed solution for A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.? has been provided alongside types of A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.? theory, EduRev gives you an ample number of questions to practice A solution of glucose in water is labelled as 10% (w/w) the density of the solution is 1.20g ml^-1 . Calculate (1) molality (2) molarity (3) mole fraction of each component in solution.? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev