10% of NaOH aqueous solution (w/w) if density =1.5g/ml Calculate :- mo...
Calculating Molarity, Molality, Mole Fraction, and % of a NaOH Aqueous Solution
Given Information:
- NaOH aqueous solution concentration: 10% (w/w)
- Density of solution: 1.5 g/mL
Calculating Molarity:
Molarity is defined as the number of moles of a solute present in one liter of a solution. To calculate molarity, we need to determine the number of moles of NaOH present in the given volume of solution.
Step 1: Calculate the mass of NaOH in the solution.
We know that the solution is 10% (w/w) NaOH. This means that for every 100 g of solution, 10 g is NaOH.
Mass of NaOH in 100 g solution = 10 g
Step 2: Calculate the number of moles of NaOH present.
We can use the molar mass of NaOH to convert the mass of NaOH to moles.
Molar mass of NaOH = 40 g/mol (Na: 23 g/mol, O: 16 g/mol, H: 1 g/mol)
Number of moles of NaOH = Mass of NaOH / Molar mass of NaOH
Number of moles of NaOH = 10 g / 40 g/mol = 0.25 mol
Step 3: Calculate the volume of solution.
We can use the density of the solution to calculate the volume.
Volume of solution = Mass of solution / Density of solution
Volume of solution = 100 g / 1.5 g/mL = 66.67 mL = 0.06667 L
Step 4: Calculate molarity.
Molarity = Number of moles of NaOH / Volume of solution
Molarity = 0.25 mol / 0.06667 L = 3.75 M
Calculating Molality:
Molality is defined as the number of moles of solute per kilogram of solvent. To calculate molality, we need to determine the number of moles of NaOH present in the solution and the mass of the solvent (water).
Step 1: Calculate the mass of water in the solution.
We know that the solution is 10% (w/w) NaOH. This means that for every 100 g of solution, 90 g is water.
Mass of water in 100 g solution = 90 g
Step 2: Convert the mass of water to kilograms.
Mass of water = 90 g = 0.09 kg
Step 3: Calculate the number of moles of NaOH present.
We already calculated this in the previous section.
Number of moles of NaOH = 0.25 mol
Step 4: Calculate molality.