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The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm?
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The cubic capacity of a four-stroke over-square spark-ignition engine ...
Calculating Bore of a Four-Stroke Over-Square Spark-Ignition Engine
Given Information:
- Cubic capacity of the engine (V) = 245 cc
- Over-square ratio (OSR) = 1.1
- Clearance volume (Vc) = 27.2 cc
We need to calculate the bore of the engine.
Formula:
The formula to calculate the cubic capacity of an engine is:
V = (π/4) x B^2 x S x (1 + (1/OSR)) + Vc
where,
V = Cubic capacity of the engine
B = Bore
S = Stroke
OSR = Over-Square Ratio
Vc = Clearance volume
We can rearrange the formula to calculate the bore as follows:
B = sqrt((4V - 4Vc)/(π x S x (1 + (1/OSR))))
Solution:
Substituting the given values in the formula,
B = sqrt((4 x 245 - 4 x 27.2)/(π x S x (1 + (1/1.1))))
B = sqrt(918.8/(π x S x 1.91))
B = sqrt(152.72/S)
We do not have the value of stroke (S) given in the question. Therefore, we need to make an assumption to proceed with the calculation.
Assumption:
Let us assume that the stroke is equal to 80% of the bore. i.e., S = 0.8B
Substituting this value in the above equation, we get:
B = sqrt(152.72/(0.8B))
B^2 = 191.44
B = 13.83 cm (approx)
Therefore, the bore of the engine is approximately 13.83 cm.
Conclusion:
In this question, we were given the cubic capacity, over-square ratio, and clearance volume of an engine, and we needed to calculate the bore. Using the formula for cubic capacity and assuming a value for stroke, we were able to calculate the bore of the engine to be approximately 13.83 cm.
Given Information:
- Cubic capacity of the engine (V) = 245 cc
- Over-square ratio (OSR) = 1.1
- Clearance volume (Vc) = 27.2 cc
We need to calculate the bore of the engine.
Formula:
The formula to calculate the cubic capacity of an engine is:
V = (π/4) x B^2 x S x (1 + (1/OSR)) + Vc
where,
V = Cubic capacity of the engine
B = Bore
S = Stroke
OSR = Over-Square Ratio
Vc = Clearance volume
We can rearrange the formula to calculate the bore as follows:
B = sqrt((4V - 4Vc)/(π x S x (1 + (1/OSR))))
Solution:
Substituting the given values in the formula,
B = sqrt((4 x 245 - 4 x 27.2)/(π x S x (1 + (1/1.1))))
B = sqrt(918.8/(π x S x 1.91))
B = sqrt(152.72/S)
We do not have the value of stroke (S) given in the question. Therefore, we need to make an assumption to proceed with the calculation.
Assumption:
Let us assume that the stroke is equal to 80% of the bore. i.e., S = 0.8B
Substituting this value in the above equation, we get:
B = sqrt(152.72/(0.8B))
B^2 = 191.44
B = 13.83 cm (approx)
Therefore, the bore of the engine is approximately 13.83 cm.
Conclusion:
In this question, we were given the cubic capacity, over-square ratio, and clearance volume of an engine, and we needed to calculate the bore. Using the formula for cubic capacity and assuming a value for stroke, we were able to calculate the bore of the engine to be approximately 13.83 cm.
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The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm?
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The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm?.
The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The cubic capacity of a four-stroke over-square spark-ignition engine is245 cc. The over-square ratio is 1.1. The clearance volume is 27.2 cc. Calculate the bore. 2 points 7 cm 7.5 cm 6.4 cm 7.2 cm?.
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