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If (x + a) is a factor of both the quadratic polynomials x2 + px + q and x2 + lx + m, where p, q, l and m are constants, then which one of the following is correct ? 
  • a)
    a = (m – q)/ (l – p) (l ≠ p)
  • b)
    a = (m + q) / (l + p) (l ≠ p)
  • c)
    l = (m – q) / (a – p) (a ≠ p)
  • d)
    p = (m – q) / (a – l)  (a ≠ l)
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If (x + a) is a factor of both the quadratic polynomials x2 + px + q a...
Explanation:
- Given: (x + a) is a factor of both x^2 + px + q and x^2 + lx + m
- Since (x + a) is a factor of x^2 + px + q, we have:
x^2 + px + q = (x + a)(x + k) where k is a constant
- Expanding the above equation, we get:
x^2 + px + q = x^2 + (a + k)x + ak
- Comparing coefficients of x in both equations, we get:
p = a + k and q = ak
- Since (x + a) is a factor of x^2 + lx + m, we have:
x^2 + lx + m = (x + a)(x + n) where n is a constant
- Expanding the above equation, we get:
x^2 + lx + m = x^2 + (a + n)x + an
- Comparing coefficients of x in both equations, we get:
l = a + n and m = an
- Solving the above equations simultaneously, we get:
a = (m - q)/(l - p)
Therefore, the correct answer is option 'A': a = (m - q)/(l - p).
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If (x + a) is a factor of both the quadratic polynomials x2 + px + q and x2 + lx + m, where p, q, l and m are constants, then which one of the following is correct ?a)a = (m q)/ (l p) (l p)b)a = (m + q) / (l + p) (l p)c)l = (m q) / (a p) (a p)d)p = (m q) / (a l) (a l)Correct answer is option 'A'. Can you explain this answer?
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