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A 2-stroke oil engine has bore pf 20 cm, stroke 30 cm, speed 350 r. p. m, i. m. e. p 275 kN/m2, net brake load 610 N, diameter of brake drum 1m,oil consumption 4.25 kg/hr, calorific value of fuel 44. 103 kj/kg. The indicated thermal efficiency will be?
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A 2-stroke oil engine has bore pf 20 cm, stroke 30 cm, speed 350 r. p....
Indicated Thermal Efficiency of a 2-Stroke Oil Engine





Given data:

Bore (d) = 20 cm

Stroke (l) = 30 cm

Speed (N) = 350 r.p.m

IMEP (p) = 275 kN/m2

Net Brake Load (Pb) = 610 N

Diameter of Brake Drum (D) = 1 m

Oil Consumption (m) = 4.25 kg/hr

Calorific Value of Fuel (CV) = 44.103 kJ/kg

Formula:

Indicated Thermal Efficiency (ηi) = Pb x LHV / m x CV x 3600

where, LHV is the Lower Heating Value of fuel




Calculation:

The stroke length in metres (L) is:

L = l / 100

L = 30 / 100

L = 0.3 m

The swept volume (Vs) is:

Vs = π/4 x d2 x L

Vs = 3.14/4 x (0.2)2 x 0.3

Vs = 0.0188 m3

The engine displacement (Vd) is:

Vd = Vs x N / 2

Vd = 0.0188 x 350 / 2

Vd = 3.29 m3/min

The mass of fuel burned per minute (mf) is:

mf = m / 60

mf = 4.25 / 60

mf = 0.071 kg/min

The Brake Mean Effective Pressure (BMEP) is:

BMEP = Pb x 2π x L x N / 60 x d2

BMEP = 275 x 2π x 0.3 x 350 / 60 x (0.2)2

BMEP = 1955.76 kPa

The Brake Power (P) is:

P = Pb x 2π x N x D x Pb / 60 x 1000

P = 610 x 2π x 350 x 1 / 60 x 1000

P = 11.96 kW

The Lower Heating Value (LHV) is:

LHV = CV - 2440 x (0.065 + 0.008 x (CV / 44.7))

LHV = 44.103 - 2440 x (0.065 + 0.008 x (44.103 / 44.7))

LHV = 41.477 MJ/kg

Now, putting all the values in the formula for Indicated Thermal Efficiency:

ηi = Pb x LHV / m x CV x 3600

ηi = 610 x 41.477 x 1000 / 0.071 x 44.103 x 3600

ηi = 31.93%

Therefore, the indicated thermal efficiency of the 2-stroke oil engine is 31.93%.
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A 2-stroke oil engine has bore pf 20 cm, stroke 30 cm, speed 350 r. p. m, i. m. e. p 275 kN/m2, net brake load 610 N, diameter of brake drum 1m,oil consumption 4.25 kg/hr, calorific value of fuel 44. 103 kj/kg. The indicated thermal efficiency will be?
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