Computer Science Engineering (CSE) Exam  >  Computer Science Engineering (CSE) Questions  >  Given an undirected graph G with V vertices a... Start Learning for Free
Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices is
  • a)
    E
  • b)
    2E
  • c)
    V
  • d)
    2V
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Given an undirected graph G with V vertices and E edges, the sum of th...
Since the given graph is undirected, every edge contributes as 2 to sum of degrees. So the sum of degrees is 2E.
Free Test
Community Answer
Given an undirected graph G with V vertices and E edges, the sum of th...
Explanation:

Let di be the degree of vertex i. Then, the sum of the degrees of all vertices is given by:

Σdi

Now, each edge contributes a degree to two vertices, since an edge connects two vertices. Therefore, the total number of degrees is twice the number of edges:

2E

Also, the total number of degrees is equal to the sum of the degrees of all vertices:

Σdi

Therefore, we have:

Σdi = 2E

Now, since the graph is undirected, the sum of the degrees of all vertices is equal to twice the number of edges:

Σdi = 2E

Therefore, the sum of the degrees of all vertices is equal to 2E.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Question Description
Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Given an undirected graph G with V vertices and E edges, the sum of the degrees of all vertices isa)Eb)2Ec)Vd)2VCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev