Four times the ninety first term of an arithmetic progression is equal...
Problem: Four times the ninety first term of an arithmetic progression is equal to 5 times it's eighty first term. If the thirty first term of the progression is -630 , find its fifty term.
Solution:
Let the first term of the arithmetic progression be 'a' and the common difference be 'd'.
Therefore, the ninety first term of the progression will be 'a + 90d' and the eighty first term will be 'a + 80d'.
Given, 4(a + 90d) = 5(a + 80d)
Simplifying the above expression, we get:
a = 50d
We know that the thirty first term of the progression is -630.
Therefore, substituting the values of 'a' and 'd', we get:
50d + 30d = -630
80d = -630
d = -7.875
Substituting the value of 'd' in the equation 'a = 50d', we get:
a = -393.75
Therefore, the arithmetic progression is: -393.75, -401.625, -409.5, ...
To find the fiftieth term, we use the formula:
T50 = a + 49d
Substituting the values of 'a' and 'd', we get:
T50 = -393.75 + 49(-7.875)
T50 = -393.75 - 386.625
T50 = -780.375
Therefore, the fiftieth term of the progression is -780.375.
Answer: The fiftieth term of the arithmetic progression is -780.375.
Four times the ninety first term of an arithmetic progression is equal...
4(a+90d)=5(a+80d)
4a+360d=5a+400d
a=-40d...(1)
[a+30d=-630]...(given)....(2)
Putting value of (1) in equation (2);
-40d+30d=-630
-10d=-630
d=63
a=-40(63)
a=-2520
....50th term=>a+49d
-2520+49(63)
3087-2520
567...(Required Answer!)
To make sure you are not studying endlessly, EduRev has designed CAT study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CAT.